Grace bought 6.9 ounces of chocolate. 0.7 ounces of it was milk chocolate and the rest was dark chocolate. How much dark chocola
2 answers:
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Answer:
Number of student tickets sold are 57 and general tickets sold are 68.
Step-by-step explanation:
Let the number of student tickets = x and the number of general tickets = y.
It is given that in total 125 tickets were sold.
So, we have,
Also, students tickets is sold for $6 each and the general tickets are sold for $10 each.
Since, the total cost of the tickets is $1022.
So, we get,
Thus, the system of equations obtained is,
x + y = 125 ........................(1)
6x + 10y = 1022
Multiply equation (1) by 6 gives us,
6x + 6y = 750 ............................(2)
6x + 10y = 1022 .........................(3)
Subtact (2) from (3), we get,
10y - 6y = 1022 - 750
i.e. 4y = 272
i.e. y= 68.
So, equation (1) gives,
x = 125 - y
i.e. y = 125 - 68
i.e. y = 57
Hence, the number of student tickets sold are 57 and general tickets sold are 68.
<h3>Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.