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3 years ago

Can you explain to me (detailed) on how to do this problem? I will give you a brainly if you get this right.

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer:

70in^2

Step-by-step explanation:

width x height

so in this case it would be 10in x 7in

Tasya [4]3 years ago

5 0

Answer:

The answer is 70 in.

Step-by-step explanation:

To find the area of a rectangle, you have to multiply the length (in this case it's 10) and the witdh (7)

10 x 7 = 70

Thus the answer, 70.

You might be interested in

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate y' terms: $-6x^2=2yy'+y'$
[Algebra] Factor y': $-6x^2=y'(2y+1)$
[Algebra] Isolate y': $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

Step 3: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute y': $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

Step 4: Find Slope at Given Point

[Algebra] Substitute in x and y: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

2 years ago

Edmentum// monomials

stepladder [879]

Answer:

625b^6

Step-by-step explanation:

= 5^3 * 5b^6

= 5^3 * 5

= 625

6 0

3 years ago

Lindsay buys 15 3/4 gallons of gasoline for $3.50 per gallon how much the whole tank cost

nydimaria [60]

Answer:

The whole tank cost $55.13

Step-by-step explanation:

All you have to do is multiply the fraction and cost, to ge thte total cost

15 3/4 also equals 15.75 (it will be easier to multiply two fractions)

now each gall of the 15.75 costs 3.50 so we multiply the number of gallons by the cost

15.75 x 3.50 = 55.125

but now we must round since there isnt .125 cents

55.13 is the cost

4 0

3 years ago

Read 2 more answers

A sack of potatoes weighs 14 pounds 9 ounces after wendy makes potato salad for a picnic the sack weights 9 pounds 14 ounces wha

dlinn [17]

For this case we have the following conversion:
1 pound = 16 ounces
Then we rewrite the sack weights:
14 pounds 9 ounces = 14 9/16
9 pounds 14 ounces = 9 14/16 = 9 7/8
Then, we subtract both values:
(14 9/16) - (9 7/8) = 4.6875 = 4 + 0.6875
Rewriting:
4 + 0.6875 = 4 + 6875/1000
4 + 1375/200 = 4 + 275/40
4 + 275/40 = 4 + 55/8
Answer:
the weight of the potatoes wendy use for the potato salad is:
4 + 55/8 pounds

5 0

3 years ago

Graph the second equation to find the solution of the system of equations.

dsp73

Answer: (-2,2)

Explanation: I plugged it into a graphing calc!

3 0

3 years ago

Read 2 more answers