What is the ratio of two soccer balls to six footballs

Hi soooooooo give me a problem to answer

DanielleElmas [232]

Answer: what is 6709583 to the power of 568403 simplified in scientific notation and divided by 3 and graphed as a quadratic.

Step-by-step explanation: Hope this helps :)

6 0

3 years ago

Look at the following figure. Copy the cross onto another piece of paper. Then, cut apart the four pieces labeled A, B, C, and D

kozerog [31]

Answer:

C should slot on top of A.

Then D should slot in next to C of the left.

Lastly B should be beneath D and on the left of A.

Hope that makes sense.

3 0

3 years ago

Please help answer correctly !!!!!!!!! Will mark Brianliest !!!!!!!!! URGENT

krek1111 [17]

Answer:

5 00000

Step-by-step explanation:

bc it just is lolllllll

7 0

3 years ago

Let f:X → Y, where X and Y are the set of all real numbers, and x and h are real numbers.

Shkiper50 [21]

Answer:

a) f(x) = x^2

b) f(x) = x

c) any pair of numbers

Step-by-step explanation:

HI!

a)

an example of this kind of function is f(x) = x^2 because

f(x+h) = (x+h)^2 = x^2 + h^2 + 2 xh = f(x) + f(h) + 2xh

teherfore

f(x+h) ≠ f(x) + f(h)

other example is f(x) = x^n with n a whole number different than one

e.g.

f(x)=x^3

f(x+h) = (x+h)^3 = x^3 + h^3 + 3(x^2 h + x h^2) ≠ x^3 + h^3 = f(x) + f(h)

b)

f(x) = x is a function that actually behaves as indicated

f(x+h) = x + h = f(x) + f(h)

others examples of this kind of fucntion are given by multiplying x by any number:

f(x) = ax; f(x+h) = a(x+h) = ax + ah = f(x) + f(h)

c)

Any pair of numbers will make f(x+h) = f(x) + f(h), as mentioned in the previous section

lest consider 10 and 5

f(10+5) = 2 *(10+5) = 2*15 = 30

f(10) = 2*10 = 20

f(5) = 2*5 = 10

f(10) + f(5) = 20+10 = 30 = f(10+5)

5 0

3 years ago

The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar

podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50$

$d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50$

Let the 4th vertex be (x,y)

So, we have:

$d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50$

$d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50$

Equate d3 and d4

$\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}$

Take the square of both sides

$(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2$

Expand

$1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2$

Evaluate the like terms

1 + 2x + 16 + 8y = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)