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3 years ago

How do you answer this problem

Mathematics

1 answer:

sp2606 [1]3 years ago

4 0

Answer:

Step-by-step explanation:

What problem?

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Lucy’s house is located at the point shown on the coordinate grid. Ainsley’s house is located 2 units right and 3 units down fro

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Answer: 3,3

Step-by-step explanation:

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3 years ago

What is <br> 8v+w+7−8v+2w

Bingel [31]

Answer:

3w+7

Step-by-step explanation:

Let's simplify step-by-step.

8v+w+7−8v+2w

=8v+w+7+−8v+2w

Combine Like Terms:

=8v+w+7+−8v+2w

=(8v+−8v)+(w+2w)+(7)

=3w+7

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3 years ago

Please create an argument about a National Landmark/Monument. Do you think there is a monument/landmark out there that should no

Tanya [424]

Explanation:

The tallest national monument in America, it is a legendary engineering triumph, designed by Finnish-born architect Eero Saarinen. As part of the Jefferson National Expansion Memorial, the Gateway Arch serves to commemorate the accomplishments of 19th-century westward pioneers and celebrate the city’s role as the ‘Gateway to the West.’

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4 0

3 years ago

The lengths of the bases of a trapezoid are 17 inches and 10 inches. The trapezoid has an area of 189 square inches.

Mamont248 [21]

Answer:

height of this trapezoid is 14 inches.

Step-by-step explanation:

$\boxed{Area -of -trapezoid=\frac{a+b}{2} h}$

[ Here lengths, a = 17 and b = 10 and area of trapezium given 189 ]

using the formula:

$\frac{17+10}{2} *h = 189$

$\frac{27}{2} h = 189$

$h = \frac{189*2}{27}$

$h =14$

For more trapezoid related questions: https://brainly.in/question/35963763

6 0

2 years ago

Read 2 more answers

Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$

6 0

2 years ago

Read 2 more answers