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4 years ago

Need help with both of these

Mathematics

2 answers:

Maslowich4 years ago

8 0

#3:

- convert 5 pounds to ounces which equals 80 ounces

- then subtract 19 from 80

- this equals 61

You were correct

#4:

- convert 4 3/4 to ounces which equals 76 ounces

D- 76 ounces is the correct answer

Vedmedyk [2.9K]4 years ago

6 0

Answer:

3. 61 ounces

4. D. 76 ounces

Step-by-step explanation:

The oranges weigh 5 pounds which is equal to 80 ounces, the bowl weighs nineteen ounces so subtract 19 from 80 and you have the weight of the oranges

Convert 4 3/4 pounds to ounces,,,,its 76

Can someone please answer my math ASAP

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3 years ago

Read 2 more answers

Two of the vertices of a rectangle are (1, −6) and (−8, −6). If the rectangle has a perimeter of 26 units, what are the coordina

pantera1 [17]

Answer: $(x_1,y_1)=(1,-2)$

$(x_2,y_2)=(-8,-2)$

Step-by-step explanation:

Given

Co ordinates of vertices(1,-6) and (-8,-6)

When two points is given then Length of two points is given by

$L=\sqrt{\left ( x_2-x_1\right )^2+\left ( y_2-y_1\right )^2}$

$L=\sqrt{\left ( 1-\left ( -8\right )\right )^2+\left ( -6+6\right )^2}$

$L=\sqrt{9^2}=9 units$

Perimeter of rectangle is =26 units

Let the other side be x

thus

$2\left ( x+9\right )=26$

x+9=13

x=4 units

therefore to get the other two co ordinates

such that the length of that side is 4 units is

$(x_1,y_1)=(1,-2)$

$(x_2,y_2)=(-8,-2)$

Horizontal distance will remain same only vertical distance will change in given co ordinates to obtain the remaining two co ordinates

To verify the above two distance between two points must be 13 units

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3 years ago

PLEASE HELP! WILL MARK BRAINLIEST!

makkiz [27]

Answer:

The maximum height a rider will experience is 55 feet.

Step-by-step explanation:

Let's start writing the function that defines the path of a seat on the new Ferris wheel. This function will depend of the variable ''t'' which is time.

$X(t)=(x,y)$

In which $X(t)$ are the coordinates of the seat (the x - coordinate and the y - coordinate) that depend from time.

$''x''$ and $''y''$ are functions that depend from the variable ''t''.

For this exercise :

$X(t)=[-25sin(\frac{\pi}{30}t);-25cos(\frac{\pi}{30}t)+30]$

In order to find the maximum height a rider will experience we will study the behaviour of the y - component from the function $X(t)$ .

The function to study is $y(t)=-25cos(\frac{\pi}{30}t)+30$

To find its maximum, we will derivate this function and equalize it to 0. Doing this, we will find the ''critical points'' from the function.

⇒ $y(t)=-25cos(\frac{\pi}{30}t)+30$ ⇒

$y'(t)=\frac{5}{6}\pi sin(\frac{\pi}{30}t)$

Now we equalize $y'(t)$ to 0 ⇒

$y'(t)=0$ ⇒ $\frac{5}{6}\pi sin(\frac{\pi}{30}t)=0$

In this case it is easier to look for the values of ''t'' that verify :

$sin(\frac{\pi}{30}t)=0$

Now we need to find the values of ''t''. We know that :

$sin(0)=0\\\\sin(\pi)=0\\sin(-\pi)=0$

Therefore we can write the following equivalent equations :

$\frac{\pi}{30}t=0$ (I)

$\frac{\pi}{30}t=\pi$ (II)

$\frac{\pi}{30}t=-\pi$ (III)

From (I) we obtain $t_{1}=0$

From (II) we obtain $t_{2}=30$

And finally from (III) we obtain $t_{3}=-30$

We found the three critical points of $y(t)$ . To see if they are either maximum or minimum we will use the second derivative test. Let's calculate the second derivate of $y(t)$ :