Answer:
(20a+108)/15
Step-by-step explanation:
First find LCM of the denominators. U will find it to be 15
Then calculate the number like this.
[(14a)×1/15×1]+[(2a+36)×3/5]
[(14a/15)]+[(6a+108)/15
(14a+6a+108)/15
(20a+108)/15
We have that
0 = –2x²<span>+ 2x + 3
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Group terms that contain the same variable, and move the constant to the opposite side of the equation
(–2x²+ 2x)=-3
Factor the leading coefficient
-2*(x²-x)=-3
Complete the square. Remember to balance the equation by adding the same constants to each side
-2*(x²-x+0.25)=-3-0.50
Rewrite as perfect squares
-2*(x-0.5)²=-3.50
(x-0.5)²=-3.50/-2
(x-0.5)²=1.75------> square root both sides
(+/-)(x-0.5)=√7/2
(+)(x-0.5)=√7/2----> (√7/2)+0.5----> x=1.823
(-)(x-0.5)=√5/2-----> x=0.5-(√7/2)----> x=-0.823
the solutions are
x=1.823
x=-0.823
C I think sorry if I’m wrong
Answer:
Step-by-step explanation:
Yes
P(both red)=(10/17)(9/16)
P(both blue)=(7/17)(6/16)
P(both same)= sum of above 2 = (90+42)/(16*17)=132/(16*17)=<span>0.485
coz both same means both blue or both red
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