We can write the function in terms of y rather than h(x)
so that:
y = 3 (5)^x
A. The rate of change is simply calculated as:
r = (y2 – y1) / (x2 – x1) where r stands for rate
Section A:
rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)
rA = 12
Section B:
rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)
rB = 300
B. We take the ratio of rB / rA:
rB/rA = 300 / 12
rB/rA = 25
So we see that the rate of change of section B is 25
times greater than A
Its bh 5 time 7 = 35 is ur hight
Answer:
C a1= -2
an = an-1 +3
Step-by-step explanation:
an = -2+ (n-1)3
What is the first term? Let n=1
a1 = -2 + 0*3
a1 = -2
The difference between the terms is +3 (coefficient on (n-1))
The second term is the first term +3
The third term is the second term plus 3
The next term is the previous term +3
so an = an-1+ 3
