(a) (i) In first 4 minutes Mary's speed was 600 / 4 = 150 m / minute
(ii) in last 4 minutes her speed was (1000-600) / 4 = 400/4 = 100 m/min
(b) Marys average speed for the whole journey = 1000/8 = 125 m/min
(c) 200 m
(d) Peter arrived at school after 7 minutes . Mary took 8 minutes. Peter first.
(e) Where they met is given by where the 2 curves intersect. That is at time 6.8 minutes and 880 m from Mary's home
(f) At t= 4 dsitance between then is 600 - 400 = 200 m
Answer:
5*9
Step-by-step explanation:
5*9 duh
we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
<h3>
</h3><h3>What is the scale factor from M to S?</h3>
Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.
So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:
M = S*K
If that scale factor is 3/2, then we have the case of the problem:
M = (3/2)*S
We can isolate S in the above relation:
(2/3)*M = S
Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.
Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
If you want to learn more about scale factors:
brainly.com/question/25722260
#SPJ1
Answer:
A
Step-by-step explanation:
Don't really want you to die ^^
d = total earnings so it's the dependent/y variable
h = hours so it's the independent/x variable
9.25 = earnings per hour or slope
b = 0 since Chakan starts off with $0
Using y = mx + b...
d = 9.25h + 0 or d = 9.25h
Answer= 6ab(3b+4a)
HCM of 18 and 24=6
HCM of a and a^2 is a
HCM of b and b^2= b
So 6ab
