Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Answer:
35%
Step-by-step explanation:
To figure out the percentage of bronze medals, we must figure out the percentages of the gold and silver medals first.
We already know that 45% of the medals were silver.
We know that 4 of the 20 medals were gold.
4/20 as a percentage would be 20/100, or 20%.
So, 20% of the medals were gold, and 45% of them were silver.
45% + 20% = 65%
100% - 65% = 35%
So, 35% of the medals awarded were bronze.
<em>I would appreciate brainliest, if not that's ok!</em>
9514 1404 393
Answer:
- (5 +4 +3)×2 -1 = 23
- 5 +(4×3×2) -1 = 28
- 5×(4 +3 +2 -1) = 40
Step-by-step explanation:
The above expressions give the values you requested. I was able to form all integers 1-40 except 39.
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<em>Additional comment</em>
I used a computer program to evaluate different sequences of operations. Attached is one result for each integer 1-40 except 39. The notation here is postfix, but is not difficult to translate to infix with parentheses. Starting with the left-most operation (op), the pattern (a, b, op) → (a op b) is used. For example, the listing for 38 is 543+*21++, so this becomes 5*(4+3)+(2+1) = 38.
Answer: counting backwards, that should be -430
Step-by-step explanation: the 86th term counting backwards by 5