Hello
1 ) 3+4sinQ=6 ( Q is theta)
4sinQ=6 -3
sinQ=3/4 conclusion : Q= Arcsin(3/4)=......calculator
2 ) (2/7)cosQ =1/4
cosQ = 7/8 conclusion : Q= Arcsin(7/8)=....calculator
Answer:
<h2>Step 2</h2>
Step-by-step explanation:
Given the quadratic equation 6x² + 24x + 7 = 0, the following steps must be followed when finding the roots using the completing the square method.
Step 1: Subtract 7 from both sides
6x² + 24x + 7 - 7= 0 -7
6x² + 24x = -7
Step 2: divide through by the coefficient of x²
6x²/6 + 24x/6 = -7/6
x² + 4x = -7/6
Step 3: Add half of the coefficient of x (i.e 4/2 = 2) to both sides of the equation to complete the square of the equation x² + 4x.
x² + 4x + 2= -7/6 + 2
(x+2)² = -7/6 + 2
(x+2)² = 5/6
Step 4: taking the square root of both sides
√(x+2)² = √5/6
x+2 = ±√5/6
x = -2±√5/6
x = -2+√5/6 and -2-√5/6
Based on the conclusion above, it can be seen that Yvonne made the first error in step 2. Yvonne suppose to divide through by the coefficient of x² (i.e 6)
Answer:
y=2x-1
Step-by-step explanation:
So if you have a right triangle with legs legnth a and b
and a hypotonuse legnth c, then
a^2+b^2=c^2
given in the comments is that
a=15
c=20
input and solve
15^2+b^2=20^2
225+b^2=400
subtract 225 from boths ides
b^2=175
take square root of both sides
b=5√7
Answer:
y=2/6x-5
Step-by-step explanation:
This is because the slope is 2/6 using rise/run and the line crosses the y-axis at -5 so the b=-5 thus the equation y=2/6x-5
Your welcome!
