The area of the garden is 120 square metre
<h2>
Explanation:</h2>
The picture of the garden is shown below. In this problem, we have:
Recall that the area of a square is given by:
![A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square](https://tex.z-dn.net/?f=A_%7Bs%7D%3DL%5E2%20%5C%5C%20%5C%5C%20A_%7Bs%7D%3AArea%20%5C%20of%20%5C%20a%20%5C%20square%20%5C%5C%20L%3ASide%20%5C%20of%20%5C%20the%20%5C%20square)
On the other hand, the area of a rectangle is given by:
![A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle](https://tex.z-dn.net/?f=A_%7Br%7D%3DL_%7B1%7D%5Ctimes%20L_%7B2%7D%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Br%7D%3AArea%20%5C%20of%20%5C%20a%20%5C%20rectangle%20%5C%5C%20%5C%5C%20L_%7B1%7D%3ASide%20%5C%201%20%5C%20of%20%5C%20the%20%5C%20rectangle%20%5C%5C%20%5C%5C%20L_%7B2%7D%3ASide%20%5C%202%20%5C%20of%20%5C%20the%20%5C%20rectangle)
Therefore:
FOR THE SQUARE:
![L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}](https://tex.z-dn.net/?f=L%3D4m%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20values%3A%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Bs%7D%3D4%5E2%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Bs%7D%3D16m%5E2%7D)
FOR THE RECTANGLE 1:
![L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}](https://tex.z-dn.net/?f=L_%7B1%7D%3D6m%20%5C%5C%20L_%7B2%7D%3D4m%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20values%3A%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Br_%7B1%7D%7D%3D6%284%29%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Br_%7B1%7D%7D%3D24m%5E2%7D)
FOR THE RECTANGLE 2:
![L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}](https://tex.z-dn.net/?f=L_%7B1%7D%3D10m%20%5C%5C%20L_%7B2%7D%3D8m%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20values%3A%20%5C%5C%20%5C%5C%20%5C%5C%20A_%7Br_%7B2%7D%7D%3D10%288%29%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Br_%7B2%7D%7D%3D80m%5E2%7D)
Finally, the area of a garden is the sum of the three areas:
![A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}](https://tex.z-dn.net/?f=A_%7Btotal%7D%3DA_%7Bs%7D%2BA_%7Br_%7B1%7D%7D%2BA_%7Br_%7B2%7D%7D%20%5C%5C%20%5C%5C%20A_%7Btotal%7D%3D16m%5E2%2B24m%5E2%2B80m%5E2%20%5C%5C%20%5C%5C%20A_%7Btotal%7D%3D16%2B24%2B80%20%5C%5C%20%5C%5C%20%5Cboxed%7BA_%7Btotal%7D%3D120m%5E2%7D)
<h2>Learn more:</h2>
Area of a pizza: brainly.com/question/12878495
#LearnWithBrainly
It is false. Since you don't know what is the variable equal to. But multiplication can't be in associative property.
(x – h)² + (y – k)²<span> = r</span>²
Fill in the numbers
(x – 7)²<span> + (y +3)</span>²<span> = 49</span>
The other angle would be 35 degrees. This is because in a straight line (the wood) there are 180 degrees and when you take away 145 (the cut) you are left with 35.
180-145= 35
I hope this helps!