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stiks02 [169]
3 years ago
6

Change 6/1/4%to a fraction

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0
6. 1
_
. 4
I can't write the response understandable on this screen, I hope this is some use to u.
You might be interested in
1. Which formula defines the sequence f(1)=2, f(2)= 6, f(3)= 10, f(4)= 14, f(5)= 18?
Natasha_Volkova [10]

Answer:

f(n) =4 + f(n-1) \\for\ n>2

Step-by-step explanation:

Given

f(1)=2\\ f(2)= 6\\ f(3)= 10\\ f(4)= 14\\ f(5)= 18

Required

Determine the formula

First, we need to solve common difference (d)

d = f(n) - f(n-1)

Take n as 2

d = f(2) - f(2-1)

d = 6 - 2

d = 4

Represent each function as a sum of the previous

f(1) = 2

f(2) = 2 + 4 = f(1) + 4

f(3) = 6 + 4 = f(2) + 4

f(4) = 10 + 4 = f(3) + 4

f(5) = 14 + 4 = f(4) + 4

Represent the function as f(n)

f(n) =f(n-1) + 4

Reorder

f(n) =4 + f(n-1) \\for\ n>2

7 0
4 years ago
Anyone know this will mark brain.....pic below..
Naddika [18.5K]

Answer:

15x + 30y - 220

Step-by-step explanation:

(30 \times  \frac{1}{2} x ) + (30 \times  - 2) + (40 \times  \frac{3}{4} y )+( 40 \times  - 4)

= 15x - 60 + 30y - 160

= 15x + 30y - 60 - 160 \\  = 15x  + 30y - 220

7 0
3 years ago
The answer I got was C
defon

Answer:

it is correct

Step-by-step explanation:

8 0
3 years ago
Explain how to solve 4^x+3 = 7 using the change of base formula log base b of y equals log y over log b. Include the solution fo
Masja [62]

The value of x is 1

Explanation:

The equation is 4^x+3=7

Subtracting both sides by 3, we get,

4^x=4

Taking log on both sides, we get,

\log 4^{x}=\log 4

Rewriting the equation by 4^{x}=u

Thus, we have,

\log u=\log 4

Applying log rule, if \log f(x)=\log g(x), then f(x)=g(x)

Thus, u=4

Substituting u=4 in 4^{x}=u, we get,

4^x=4

Also, since, a^{f(x)}=a^{g(x)}, then f(x)=g(x)

Thus, x=1

Hence, the value of x is 1

7 0
3 years ago
Which of the following is a terminating decimal? Question 1 options:
Juli2301 [7.4K]
The answer for your question is c
6 0
3 years ago
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