All categories

3 years ago

Describe and correct the error, given the functions f(x)=3x-5 and g(x)=1/3-4/3x

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

The depicted evaluation is g(1) not f(1). Cross out f and write g.

Or write

f(1) = 3(1) - 5 = 3 - 5 = -2

You might be interested in

What is the quotient?

zhuklara [117]

2.943 × 10-² (negative 2nd power)

5 0

3 years ago

Read 2 more answers

Consider the quadratic function f(x)=2x^2-8x-10

Slav-nsk [51]

Answer:

f(x) = 2x² - 8x - 10.

This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:

a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex

b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)

c) VERTEX(2, - 18)

d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144

Hope this helps! :)

6 0

3 years ago

Is the dilation above an enlargement or a reduction

alexgriva [62]

Reduction...........

5 0

3 years ago

Which of the following has a constant of proportionality of 2? A) y = 2x B) y = x + 2 C) 2y = x D) y + 2 = 2x

Setler [38]

The correct answer is A.

You have direct variation if x and y are modeled by the equation

$y = mx$

In this case, m is the constant of proportionality. So, if the constant has to be 2, the equation becomes

$y = 2x$

A side note: Actually, option C has a constant of proportionality of two as well, except the roles of x and y are interchanged. I chose option A because usually you want the y = mx form, but the names of the variables are obviously meaningless.

5 0

4 years ago

Read 2 more answers

Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. Write an equation for

vivado [14]

Answer:

The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ .

Step-by-step explanation:

Given as :

The initial level of water in river = 34 feet

The rate of receding water level = 0.5 foot per day

Or, The rate of percentage of receding water level = 50 % per day

Let the level of water after d days = L

Now,

The level of water after d days = initial level of water × ( $(1-\dfrac{\textrm Rate}{100})^{Time}$

I.e L = 34 × ( $(1-\dfrac{\textrm 50}{100})^{d}$

∴ L = 34 × $(0.5)^{d}$

Hence The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ . Answer

5 0

4 years ago