Answer:
(C.
I THINK-
Step-by-step explanation:
(x-5)(x+3)=0
x^2+3x-5x-15=0
(x^2+3x) (-5x-15)
x(x+3) -5(x+3)
x-5=0 x+3=0
x=5 OR -3
Ok so...
You want to move the decimal point to the right until the number is greater than 1 but less than 10.
The number will end up being 5.2
You moved the decimal point 3 times to the right.
So it will be 5.2 x 10^-3. It is negative because you moved it to the right. The exponent would be positive if you moved it to the left
Answer:
10, it's 5 less than 5 times 3
Step-by-step explanation:
