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Dmitry [639]
3 years ago
9

Suppose a candidate for public office is favored by only 48% of the voters. if a sample survey randomly selects 2500 voters, the

percentage in the sample who favor the candidate can be thought of as a measurement from a normal curve with a mean of 48% and a standard deviation of 1%. based on this information, how often would such a survey show that 50% or more of the sample favored the candidate?
Mathematics
1 answer:
Drupady [299]3 years ago
7 0
Mean=0.48
standard deviation=0.01
thus using the z-score:
P(x>0.5) we shall have the following:
z=(0.5-0.48)/0.01=2
thus
P(x>0.5)
=1-P(x<0.5)
=1-P(z<2)
=1-0.9772
=0.0228
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<span>Twice the sum of a number and 3 = 2(n + 3)
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so
</span><span>Twice the sum of a number and 3 is equal to three times the difference of the number and 3:
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answer
2(n + 3) = 3(n - 3)
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3 years ago
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<u>Equation formed with said information:</u>

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2 years ago
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2

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