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Alexandra [31]
3 years ago
5

If the radius of a circle is 3.5 what is the area?

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

A= 12.25π or A≈ 38.48

Step-by-step explanation:

The area formula for a circle is A= πr².

A= πr²

A= π(3.5)²

A= 12.25π or A≈ 38.48

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Help? (i mark brainlist)
Bad White [126]

Answer:

A.

Step-by-step explanation:

Since it says greater than, that means that it cannot be B or D. And ≥ means greater than or equal to and they don't state that in the problem. So the answer would be A.

I HOPE THIS HELPED! :)

3 0
3 years ago
Find the quotient of x^3 + 4x^2 - x - 4 divided by x + 1
svlad2 [7]

Answer:

x^2 + 3x - 4

Step-by-step explanation:

solved using long division

4 0
3 years ago
Help photo question. Mathematics. :D
Aleks04 [339]
M = 4
n = 1

If you substitute in your values, you can see that 4 + 1 = 5
And 4 - 1 = 3
Hope this helped :)
5 0
3 years ago
F has 10 more marbles than I. Both boys have 15 marbles combined. How many marbles does each boy have?
olganol [36]

Answer:

F has 10 marbles and I has 5 marbles.

Step-by-step explanation:

First, I subtracted 10 from 15 since F has 10  more marbles than I. When I subtracted I got 5.

Hope this helps!!!!

4 0
3 years ago
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
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