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3 years ago

How do you make an equivalent fraction to another fraction?

1 answer:

7 0

<span>You can make equivalent fractions by multiplying or dividing both top and bottom by the same amount.You only multiply or divide, never add or subtract, to get an equivalent fraction.<span>Only divide when the top and bottom stay as whole numbers.

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6x-7y= -2 please help me

Nana76 [90]

Answer:

X=7/6y+-1/3

Step-by-step explanation:

It will be hard for me to demonstrate the equation

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4 years ago

What is ___x5=20 3x _____=6 2+ ____=16 3x____=24 9x____=34 12+____=2

nydimaria [60]

Answer:

4×5=20

3×2=6

2+14=16

3×8=24

9×4=36, 36 -2 = 34

12+(-10) =2

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3 years ago

ANSWER ALL TO GET ALL POINTS

maw [93]

Answer:

hypotenuse is always opposite the right angle and it is always the longest side of the triangle

Pythagorean Triple consists of three positive integers a, b, and c, such that a² + b² = c² example 3, 4, 5).

volume occupies a three dimensional space. Distance is measured in one unit of length

Step-by-step explanation:

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3 years ago

The volumes of two similar figures 27mm^3 and 1331mm^3. If the surface area of the smaller figure is 18mm^2, what is the surface

nlexa [21]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\$

$\bf \cfrac{small}{large}\qquad \cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\qquad thus\qquad \cfrac{\sqrt[3]{27}}{\sqrt[3]{1331}}=\cfrac{\sqrt{18}}{\sqrt{a}}
\\\\\\
\cfrac{3}{11}=\sqrt{\cfrac{18}{a}}\implies \left( \cfrac{3}{11} \right)^2=\cfrac{18}{a}\implies \cfrac{3^2}{11^2}=\cfrac{18}{a}\implies a=\cfrac{11^2\cdot 18}{3^2}$

and surely, you know how much that is.

6 0

4 years ago

The perimeter of the triangle shown are equal. Find the side lengths of each triangle.

Lunna [17]

Good morning ☕️

___________________

Step-by-step explanation:

Let p1 be the perimeter of triangle ABC

p2 be the perimeter of triangle PQR

p1=(2x+4)+(2x+3)+(2x) = 6x+7

p2=(2x)+(2x)+(3x+1) = 7x+1

p1=p2 ⇔ 6x+7=7x+1 ⇔ 7x-6x=7-1 ⇔x=6

Then :

AC=2(6)=12

AB=2(6)+4=16

BC=2(6)+3=15

PQ=12

QR=12

PR=3(6)+1=19.

_____

6 0

3 years ago

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