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d1i1m1o1n [39]
3 years ago
7

My number has a tens digit that is 8 more than the ones digit. Zero is not one of my digits. Write the 2-digit number that match

es the clues

Mathematics
2 answers:
pochemuha3 years ago
6 0

Answer:

The number is 91

Step-by-step explanation:

Let x be the ones place digit and y be the tens place digit,

Then the number would be 10y + x,

We have,

y - x = 8

Possible values of y and x = { (8, 0), (9, 1) }

∵ 0 is not the digit of the number,

Hence, y = 9 and x = 1

Therefore, required number = 10(9) + 1 = 90 + 1 = 91

steposvetlana [31]3 years ago
5 0

The requested number is: <u><em>91 </em></u>

<h3>Further explanation </h3>

Numbers are quantities used in measurements

Numbers in mathematics can be divided into several terms

  • 1. integer

numbers consist of positive, negative and 0 numbers

  • 2. natural numbers

numbers consisting of positive numbers, starting with number 1

  • 3. whole number

a number consists of positive numbers and zeros

  • 4. prime number

numbers that can only be divided by numbers themselves and the number 1

And examples of other numbers such as imaginary numbers, real numbers, rational numbers, etc.

Integers themselves consist of

  • 1. positive integers

the number to the right of the number 0 is 1,2,3 ...

  • 2. negative integers

the numbers to the left of the zeros are -1, -2, -3 ...

  • 3. number 0

From the above questions we can separate into several sections:

  • Write the 2-digit number that matches the clues

Means the number requested consists of 2 numbers, let us suppose the tens = x and the ones = y, so the number is<em><u> </u></em><em><u>xy </u></em>

  • My number has a tens digit that is 8 more than the ones digit

we can translate this sentence into the equation:

x = y + 8

So from the numbers 0 to 9 that have a difference of 8 to fill the values ​​of x and y are

  • 0 and 8
  • 1 and 9

because Zero is not one of my digits, the most appropriate numbers x and y are <u>1 and 9 </u>

So the number requested is \large{\boxed{\bold{xy=91}}

<h3>Learn more </h3>

Express 0.000431 L answer as an integer

brainly.com/question/10876135

type of number

brainly.com/question/12788761

Classify the number as a natural, whole, integer, rational, or irrational.

brainly.com/question/2731293

 

Keywords: integer, digit, the tens, the ones, number

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
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Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
what is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0? o (-12,-2) o (-6, -1) o (6, 1) (12, 2)
Leno4ka [110]

Answer:

(6,1)

Step-by-step explanation:

1.) group the x and y terms (and move the constant to the other side)

x²-12x+y²-2y= -12

divide the coeficcents for the terms with just 1 or 1 x variable by 2 and then square it (and add that to both sides)

x²-12x+36+y²-2y+1= -12+36+1

factor

(x-6)²+(y-1)²= 25

the center is therefore (6,1)

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The answer to the question

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Answer:

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The relationship is linear,

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y=-1/2(6)-4

y=-6/2-4

y=-3-4

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8 0
3 years ago
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