Answer:
Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft
Step-by-step explanation:
Amount of sausage links made on Friday morning = 8 ft
Amount of sausage links used on Friday night = 4 ft
Amount of sausage links remaining = 8 - 4 = 4ft (i)
Amount of sausage links made on Saturday morning = 8 ft (ii)
So,
Total amount of sausage links = 8 + 4 = 12 ft (from (i) and (ii) )
Amount of sausage links used on Saturday night = 12 ft
Amount of sausage links remaining = 12 - 12 = 0 ft
Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft
Y=2 by the method of substitution (x is 7).
Either heads or tails so there is a 50/50 chance of both
1. 4 (6 + 7) is the same as (4 • 6) + (4 • 7)
X = 4
2. 6 • 45 = 270
a. 270, (6 • 40) + (6 • 5) = 240 + 30 = 270
b. 210, (6 • 40) - (6 • 5) = 240 - 30 = 210
c. 270, (6 • 50) - (6 • 5) = 300 - 30 = 270
A. 270, C. 270
3. 6m + 7n + 5m - 3n, combine like terms, 6m + 5m = 11m, 7n - 3n = 4n
B. 11m + 4n
4. 2y<u>^3</u> - 4y^2 + y + y<u>^3</u>, exponents tell you what are like terms
C. 2y^3 and y^3
5. 4x<u>^3</u> - 3x^2 + x + 3x<u>^3</u>, combine like terms, then put in descending order
D. 7x^3 - 3x^2 + x
Answer:
74.30
Step-by-step explanation:
Let s = entry price for a student
Let t = entry price for a teacher
4s +5t = 95
6s+10t = 173
I will use elimination to solve this problem.
Multiply the first equation by -2
-2(4s +5t) = -2*95
Distribute
-8s - 10t = -190
Add this equation to the second equation to eliminate t
-8s - 10t = -190
6s+10t = 173
----------------------
-2s = -17
Divide by -2
-2s/-2 = -17/-2
s = 8.50
Now we need to find t
4s +5t = 95
Substitute s=8.50
4(8.50) +5(t) = 95
34 +5t = 95
Subtract 34 from each side
34-34 +5t = 95-34
5t = 61
Divide by 5
5t/5 = 61/5
t = 12.20
We want to find the cost for 3 students and 4 teachers
3s+4t
3(8.50) + 4(12.20)
25.50 + 48.80
74.30
