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3 years ago

Simplify the following expression. x^-1

Mathematics

1 answer:

tia_tia [17]3 years ago

5 0

∧ -1
X = 1/2 X

Answer = 1/2 x

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consider these graphs: Eric thinks the equation y=(x-3)^2 will match the blue graph. Jenney thinks it will match the red graph.

Dimas [21]

Answer: Jenny

Step-by-step explanation:

By subtitue Y = 0

0=(x-3)^2

And you get 3

3 0

3 years ago

Solving radical equation

Darya [45]

$\bf \sqrt{k-9}-\sqrt{k}=-1\implies \sqrt{k-9}=\sqrt{k}-1\impliedby \textit{squaring both sides}
\\\\\\
(\sqrt{k-9})^2=(\sqrt{k}-1)^2\implies k-9=(\sqrt{k}-1)(\sqrt{k}-1)\impliedby \textit{FOIL}
\\\\\\
k-9=k-2\sqrt{k}+1\implies -10=-2\sqrt{k}\implies \cfrac{-10}{-2}=\sqrt{k}
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\sqrt{\cfrac{-10}{-2}}=k$

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4 years ago

75. Simplify the expression: -2x(4x^2 - 5x + 3)

Karolina [17]

-2x(4x² - 5x + 3) Distribute/multiply -2x into (4x² - 5x + 3)

(4x²)(-2x) - (5x)(-2x) + (3)(-2x)

-8x³ + 10x² - 6x

Your answer is the 3rd option

3 0

3 years ago

Find the other two zeroes of the polynomial x4 - 5x + 2x2 + 10x - 8, if it Is given that the two zeroes are - √2 and √2

SVEN [57.7K]

Answer:

$\large\boxed{\{-\sqrt2,\ 1,\ \sqrt2,\ 4\}}$

Step-by-step explanation:

$W(x)=x^4 - 5x^3 + 2x^2 + 10x - 8$

Let's look for zeros in constant term dividers.

List of 8 divisors:

$\{\pm1,\ \pm2,\ \pm4,\ \pm8\}$

Check:

$W(1)=1^4-5(1)^3+2(1)^2+10(1)-8=1-5(1)+2(1)+10\\\\=1-5+2+10-8=0\\\\W(-1)=(-1)^4-5(-1)^3+2(-1)^2+10(-1)-8=1-5(-1)+2(1)-10-8\\\\=1+5+2-10-8=-10\neq0\\\\W(2)=2^4-5(2)^3+2(2)^2+10(2)-8=16-5(8)+2(4)+20-8\\\\=16-40+8+20-8=-4\neq0\\\\W(-2)=(-2)^4-5(-2)^3+2(-2)^2+10(-2)-8\\\\=16-5(-8)+2(4)-20-8=16+40+8-20-8=36\neq0\\\\W(4)=4^4-5(4)^3+2(4)^2+10(4)-8=256-5(64)+2(16)+48-8\\\\=256-320+32+40-8=0$

We found missing zeros. Therefore, we do not check the remaining numbers.

8 0

4 years ago

Question 8 of 25

lisabon 2012 [21]

Answer: the y-intercept is (0,4)

Step-by-step explanation:

6 0

3 years ago