Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Any quadrilateral has sum of all angles equal 360⁰.
So,
m∠D+78+91+90=360
m∠D=360-(78+91+90)=101⁰
Answer is A.
Answer: y = -3x-3 (Choose values for x)
Step-by-step explanation:
1st change the equation to y = mx+b form
In order to change the equation to y = mx+b form subtract the 3x to both sides.
The equation now becomes y = -3x-3
2nd we can either choose values for x such has (-2,-1,0,1,2) and plug in those values into our equation y = -3x-3
For example, if we plug in x= -2 we get y= -3(-2)-3 which becomes y =3. We then plot the point (-2,3) because -2 is our x coordinate and 3 is our y coordinate.
Or we can plug the equation into a calculator that will graph the equation for you.
Part A:
The circumference of the circle is 197.92.
Explanation:
The formula for circumference of a circle is C=2 πr. If you insert the numbers, it would be C=2 x 3.14 x 31.5. Hence, the answer is 197.92.
Part B:
The area is 3117.25 square cm.
Explanation:
The formula for area of a circle is A= πr ². Inserting the numbers, it is A=3.14 x 31.5 ². Therefore the answer is 3117.25 cm ².
Since you are given that the student registered early, the total number you deal with is all students who registered early.
211 + 329 = 540
number of undergraduates who registered early = 211
Among students who registered early:
p(undergraduate) = 211/540