Question

A physical therapist is scheduling appointment for the day. She has six workers comp cases six Medicare patients awaiting care. If she choose we seven at random for her morning schedule, find the probability that she’ll pick three worker’s comp cases and four Medicare patients. Round your answer to five decimal places.

Answer 1

Answer:

Pr(3worker's comp cases and 4 Medicare patients) = 0.37879

Step-by-step explanation:

Number of worker’s comp cases = 6

Number of Medicare patients = 6

Total  number of people = 6 + 6 = 12

Total number of ways of selecting 7 people from 12 people = 12C7

Total number of ways of selecting 7 people from 12 people = $\frac{12!}{(12-7)!7!}$

Total number of ways of selecting 7 people from 12 people = 792 ways

Number of ways of selecting 3 worker's comp cases = 6C3

Number of ways of selecting 3 worker's comp cases =  $\frac{6!}{(6-3)!3!}$

Number of ways of selecting 3 worker's comp cases = 20 ways

Number of ways of selecting 4 Medicare patients= 6C4

Number of ways of selecting 4 Medicare patients =  $\frac{6!}{(6-4)!4!}$

Number of ways of selecting 4 Medicare patients = 15 ways

Pr(3worker's comp cases and 4 Medicare patients) = (15*20)/792

Pr(3worker's comp cases and 4 Medicare patients) = 300/792

Pr(3worker's comp cases and 4 Medicare patients) = 0.37879