<em>Measure the length, width, and depth of an object in inches. ...
</em>
<em>Write the length of your object. ...
</em>
<em>Multiply the length by the width of your object. ...
</em>
<em>Multiply your answer by the depth of your object. ...
</em>
<em>Label your answer in cubic inches.</em>
Well when you multiply it, it would equal 90 and 5*18 is 90 then you subtract 40 and you would get 50
SO YOUR ANSWER IS >>18<<
Answer:
yes
Step-by-step explanation:
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Answer:
We choose C
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo
Basically, interquartile range represents the width or "dispersion" of the set. [1] The interquartile range is determined by the difference between the top quartile (25% highest) and lower quartile (25% lowest) point of the data set.
From the picture, we can find that:
- The interquartile range of the bus drivers is: 20 -10 = 10
- The interquartile range of the teachers is: 30 -15 = 15
So the interquartile range of the distances for the bus drivers is 5 miles less than the interquartile range of the distances for the teachers.
We choose C
Answer:
(x-8)(x+4)/(x+4) = (x-8)
Step-by-step explanation:
x+4 cancel out and you get x-8