To draw a histogram, you need two axes. The horizontal axis is the day and the vertical axis is the number of text messages. For the first day, there are 20 text messages. This is represented by a bar starting from the horizontal axis labeled Day 1 going up to the point where the vertical axis indicates 20 text messages. This is done for the rest of the data. Afterwards, a line is drawn from the vertex of the axes connected to the top of the first bar. Then from the top of the first bar, a line connects it to the top of the next bar. This is done for all the bars before producing a histogram.

6 0

3 years ago

The label on the cars antifreeze container claims to protect the car between -30C and 130C. To convert Celsius temperature to Fa

RideAnS [48]

C = 5/9(F - 32)

C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F

C = 5/9(F - 32)
C = 130

130 = 5/9F - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F

So in Fahrenheit temp, the the car is protected between -22 F and 266 F

4 0

3 years ago

Read 2 more answers

I need help plz. Its DeMoivres Theorem

vagabundo [1.1K]

$\bf \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ z=\stackrel{a}{-1}\stackrel{b}{-\sqrt{3}~i}~~ \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right)\\[-0.5em] \hrulefill\\ r=\sqrt{(-1)^2+(\sqrt{3})^2}\\ \qquad \sqrt{4}\\ \qquad 2\\ \theta =tan^{-1}\left( \frac{-\sqrt{3}}{-1} \right)\\\\ \qquad \frac{4\pi }{3} \end{cases}$

$\bf z=2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right]\implies z^6=\left[ 2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right] \right]^6 \\\\\\ z^6=2^6\left[ cos\left( 6\cdot \frac{4\pi }{3} \right) -i~sin\left( 6\cdot \frac{4\pi }{3} \right)\right]\implies z^6=64[cos(8\pi )-i~sin(8\pi )] \\\\\\ z^6=64[(-1)-i~(0)]\implies z^6=\stackrel{\stackrel{a}{\downarrow }}{-64}~~\stackrel{\stackrel{b}{\downarrow }}{-0i}$

4 0

4 years ago