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denpristay [2]
3 years ago
6

I will give brainliest to whoever answers this!!

Mathematics
1 answer:
Reika [66]3 years ago
4 0
The first one is g=1, the second is identity, and the third one is b=0.
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Can you help me with explanation will give brainiest
Ipatiy [6.2K]

Answer:

Area of rectangular garden = lxb = 10*5

                                             = 50 sq. inch

when area increases by six times

new area = 50*6 = 300 sq inches

now,

let x be increasement in both  length and width

(5+x) (10+x) = 300

50 + 5x + 10x + x² = 300

x² + 15x - 250 = 0

x²+ 25x-10x -250 = 0

x(x+25) - 10 (x+25) = 0

( x-10) (x+25) = 0

either x + 25 =0

x = -25 length can be negative

0r x-10 = 0

x = 10

so 10 inches is increase on both side

Step-by-step explanation:

6 0
3 years ago
Is the following statement true? Explain.
sukhopar [10]

Step-by-step explanation:

We can prove the statement is false by proof of contradiction:

We know that cos0° = 1 and cos90° = 0.

Let A = 0° and B = 90°.

Left-Hand Side:

cos(A + B) = cos(0° + 90°) = cos90° = 0.

Right-Hand Side:

cos(A) + cos(B) = cos(0°) + cos(90°)

= 1 + 0 = 1.

Since LHS =/= RHS, by proof of contradiction,

the statement is false.

4 0
3 years ago
ASAP PLSSS help me with this math question
rjkz [21]

Answer:

Answer is D

Step-by-step explanation:

just took the test and got it right

Please mark brainlest

8 0
3 years ago
Determine if the following triangle is a right triangle or not using the Pythagorean Theorem Converse. Triangle with side length
Nadusha1986 [10]

Answer:

It is a right triangle

Step-by-step explanation:

Information needed:

Formula: a^2+b^2= c^2

a: leg

b: leg

c: hypotenuse

the longest side is always the hypotenuse, so 17 in

the order of legs don't matter so 8 in and 15 in

Solve:

a^2+b^2= c^2

8^2+15^2= 17^2

64+225= 289

289= 289

Final answer:

It is a right triangle

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAP!!
solong [7]
We have to find midpoint M of the diagonal AC (or BD, there is no difference) so:

M=\left(\dfrac{x_A+x_C}{2},\dfrac{y_A+y_C}{2}\right)=\left(\dfrac{-2+4}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{2}{2},\dfrac{2}{2}\right)=\\\\\\=\boxed{(1,1)}
5 0
4 years ago
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