Maya runs 100m in 13.4s and Amy can run 100m in 14.1s. If Amy were to finish a 100m race at the same time as Maya, how much of a
head start, in meters, will Amy need? What information is known and unknown? and what proportion can you write to solve this problem?
1 answer:
In this case we will use the general equation:
d = s t (distance =
speed*time)
Therefore
Distance Amy can run in 13.4s:
d = (100m/14.1s)*(13.4s)
d = 95.04meters
Headstart needed = total distance - distance run in 13.4s
(time Maya runs 100m)
headstart needed = 100-95.04 = 4.96meters
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