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DedPeter [7]
3 years ago
12

Please help me please​

Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

Weight and force due to gravity.

I hope it helps.

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Samantha has 23 strawberries and wants to put 4 strawberries into each bowl. How many bowls can Samantha put exactly 4 strawberr
Bogdan [553]

4 cannot go into 23 equally BUT! if you do 23 divided by 4 you'll get 5.75 which rounds up to 6. So on average she'll need 6 bowls for her 23 strawberries.

Edit: It should be 5 bowls because if she wants to put an equal amount of strawberries into her bowls it should be 5.

Hope it helped. :)

<em>~Noodles~</em>

8 0
3 years ago
It is a little blurry
Yanka [14]

Answer:

i think 120, im not quite sure, im not the best at this

Step-by-step explanation:

4 0
3 years ago
If the 5 digit number 1732p is divisible by 9, then p =<br> O 3<br> O 5<br> O 7<br> O 4
OlgaM077 [116]

Answer:

p = 5

Step-by-step explanation:

1732(5)/9 = 1925

8 0
3 years ago
Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+
Hoochie [10]
The vertex form of the equation of a parabola is given by

y-k=a(x-h)^2

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

y-(-2)=a(x-(-12))^2 \\  \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\  \\ y=ax^2+24ax+114a-2 \\  \\ y=x^2+24x+ \frac{114a-2}{a}

For a = 1,

y=x^2+24x+112

<span>The parabola whose minimum is at (−12,−2) is given by the equation y=x^2+ax+b, where a = 24 and b = 112.</span>
8 0
4 years ago
The area of the postcard is 24 square inches. What is the width b of the message (in inches)?
MAXImum [283]
Area of rectangular post card = length x width
For the given post card: 
length = 4 in
width = (3+b) in
area = 24 in^2

So, substituting in the equation of the area:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in

Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
4 0
4 years ago
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