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3 years ago

What is the value of 13 x [ 4 + (9-2)]?

Mathematics

1 answer:

RideAnS [48]3 years ago

4 0

Answer:

$13*[4+(9-2)]=143$

Step-by-step explanation:

we have

$13*[4+(9-2)]$

step 1

Solve $(9-2)$

$(9-2)=7$

substitute

$13*[4+7]$

step 2

Solve $[4+7]$

$[4+7]=11$

substitute

$13*[11]$

step 3

Solve $13*11$

$13*11=143$

therefore

$13*[4+(9-2)]=143$

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The two posts are parallel lines. The ground is a transversal.

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3 years ago

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Answer:

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3 years ago

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Margaret [11]

Answer:

<h2>a.) reflect across x-axis</h2>

Step-by-step explanation:

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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3 years ago

How to solve this question. I need to show my work for this question.

IrinaK [193]

Step-by-step explanation:

Recall that 1 dozen = 12 so 4 dozen cookies has a total of 48 cookies. We are going to use the following ratios to solve the problem:

$\left(\dfrac{3\:\text{eggs}}{48\:\text{cookies}}\right)$ and $\left(\dfrac{48\:\text{cookies}}{3\:\text{eggs}}\right)$

a) $12\:\text{eggs}×\left(\dfrac{48\:\text{cookies}}{3\:\text{eggs}}\right) = 192\:\text{cookies}$

b) 18 dozen cookies = 216 cookies

$216\:\text{cookies}×\left(\dfrac{3\:\text{eggs}}{48\:\text{cookies}}\right) = 13.5\:\text{eggs}$

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3 years ago