A line passes through the points (9,6) and (6,5). What is its equation in slope-intercept form?

Mathematics

1 answer:

Tju [1.3M]2 years ago

5 0

Answer:

Y=X/3+3

Step-by-step explanation:

M= Y2-Y1/X2-X1

= 5-6/6-9

= -1/-3

= 1/3

sub x=6, y=5, M=1/3 into Y=MX+C

5=6/3+C

5=2+C

5-2= 2+C-2

3=C

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4t+3c=$81.00 10t+3c=$135.00

muminat

$\left \{ {{4t+3c=81.00\:(I)} \atop {10t+3c=135.00\:(II)}} \right.$
Simplify the first equation by (-1)
 $\left \{ {{4t+3c=81.00\:*(-1)} \atop {10t+3c=135.00\:\:\:\:\:}} \right.$
Once simplified, cancel the opposing terms.
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-------------------------------
$6t = 54.00$
$t = \frac{54.00}{6}$
$\boxed{\boxed{t = 9.00}}\end{array}}\qquad\quad\checkmark$

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$4t+3c=81.00\:(I)$
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$3c = 81.00 - 36$
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$\boxed{\boxed{c = 15.00}}\end{array}}\qquad\quad\checkmark$

Answer:
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