Answer:
This would be an algebraic problem if that's what you're asking.
x=8 in this equation.
V = s^2 +1/2sh
Reorder so common terms are on one side.
s^2 +(sh)/2 = v
Subtract s^2 from both sides.
(sh)/2 = -s^2 +v
Multiply both sides of the equation by 2.
sh = -s^2 *2 +v *2
Simplify each term.
sh = -2s^2 +2v
Divide each term by s and simplify.
h = -2s + (2v)/s
<u>Answer:</u>
The correct answer options are A, B, C and D.
<u>Step-by-step explanation:</u>
A. Leg-angle (LA):
According to this theorem, if the leg and an acute angle of one right triangle are congruent to the corresponding leg and acute angle of another right triangle, then the triangles are congruent.
B. Hypotenuse-leg (HL):
If any two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.
C. Hypotenuse-angle (HA):
If the hypotenuse and an acute angle of one right triangle are congruent to the hypotenuse and an acute angle of another right triangle, then the two triangles are congruent.
D. Leg-leg (LL):
If any two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.
Multiply both numerator and denominator with 8+5i. Then you get
Answer:
TU= 8
WU=10
TX=5
TV=10
Step-by-step explanation:
