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3 years ago

2. Simplify the following expression. – 2(3x – 5) – 12x - 2

Mathematics

1 answer:

aniked [119]3 years ago

3 0

Answer:

-18x+8

Step-by-step explanation:

First you have to distribute the -2 to the 3x and the -5 in the parenthesis giving you -6x+10-12x-2.

Next you combine like terms which gives you -18x+8

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Question 5 of 10

suter [353]

C. Similar -SAS is the answer I think

8 0

3 years ago

PLEASE HELP I HAVE NO CLUE WHAT IM DOING. Parents finna ground me if I don't do this tonight.

umka21 [38]

Answer:

First find x and y at given parameters:

x = (v₀cosθ)t = (123 cos60°)t = 61.5t
y = h + (v₀sinθ)t - 16t² = 0 + (123 sin 60°)t - 16t² = 106.52t - 16t²

Maximum height is at vertex. Time is:

t = -106.52/-32 = 3.3 seconds

Maximum height is:

y = 106.52*3.3 - 16(3.3)² = 177.3 ft

Horizontal distance:

x = 61.5*3.3 = 203 feet

Time to hit the ground:

106.52t - 16t² = 0
16t = 106.52 (t = 0 is discounted)
t = 106.52/16
t = 6.7 seconds

5 0

3 years ago

For any positive number b not equal to 1 and any number or variable n, evaluate the following expression.

kirza4 [7]

Answer:

$log_{b} b^{n}$ = n.

Step-by-step explanation:

Given : $log_{b} b^{n}$ , b is any positive number not equal to 1 and n is any number.

To find : Evaluate the expression $log_{b} b^{n}$ .

Formula used : $log_{b} x^{y}$ . = y ∙ $log_{b}$ (x) and

$log_{b}(b) = 1.Solution : We have [tex]log_{b} b^{n}$ .

By logarithm rule : $log_{b} x^{y}$ . = y ∙ $log_{b}$ (x).

Then $log_{b} b^{n}$ = n∙ $log_{b}$ (b).

By logarithm rule : $log_{b}(b) = 1.Now, n∙ [tex]log_{b}$ (b) = n.

Therefore, $log_{b} b^{n}$ = n.

5 0

3 years ago

Read 2 more answers

Expand the expression below to find the values of capatilised pronumerals PLS HELP :))

-BARSIC- [3]

<h2>♪Answer :</h2>

»(4x - 2y)(3x + 5y)

»4x(3x + 5y) + (-2y)(3x + 5y)

»12x² + 15xy - 6xy - 10y²

»12x² + 9xy - 10y²

so, ABC is :

A = 12✅
B = 9✅
C = -10✅

6 0

3 years ago

Help help help help help

wariber [46]

Answer:

Step-by-step explanation:

1) (-6 , 2) ; (3 , -5)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{-5-2}{3-[-6]}\\\\= \frac{-5-2}{3+6}\\\\= \frac{-7}{9}\\$

m = -7/9 ; (-6 , 2)

y - y₁ = m(x -x₁)

y - 2 = (-7/9)(x - [-6])

$y - 2 = \frac{-7}{9}(x + 6)\\\\y -2 = \frac{-7}{9}x + \frac{-7}{9}*6\\\\y - 2 = \frac{-7}{9}x - \frac{7*2}{3}\\\\ y = \frac{-7}{9}x - \frac{14}{3} + 2\\\\y = \frac{-7}{9}x -\frac{14}{3} + \frac{2*3}{1*3}\\\\y = \frac{-7}{9}x - \frac{14}{3} + \frac{6}{3}\\\\y = \frac{-7}{9}x - \frac{8}{3}$

2) (3 , -4) ; m= 3

$y - y_{1} = m(x - x_{1}$ )

y - [-4] = 3(x - 3)

y + 4 = 3x - 3*3

y + 4 = 3x - 9

y = 3x - 9 - 4

Ans: y = 3x - 13

3) m = 2 ; y-intercept (b) = 3/2

y = mx + b

Ans: y = 2x + (3/2)

4) (-1, 3 ) ; (2 , 0)

Slope = $\frac{0 - 3}{2-[-1]}$

$= \frac{-3}{2+1}\\\\= \frac{-3}{3}\\\\= 1$

m = 1; ( -1 , 3)

y - 3 = 1(x -[-1])

y - 3 = 1(x + 1)

y - 3 = x + 1

y = x + 1 + 3

Ans: y = x + 4

5)(2, 1) ;m = -3

y - 1 = (-3)(x - 2)

y - 1 = -3x + 6

y = -3x + 6 +1

Ans: y = -3x + 7

5 0

3 years ago

Read 2 more answers