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dexar [7]
3 years ago
5

Find the value(s) of c such that the area of the region bounded by the parabolae y=x^2−c^2 and y=c^2−x^2 is 4608.

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
C is 12 and x is 3 and that would be your variables
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lora16 [44]

Answer:

I know the surface area is 120... don't know about volume

5 0
3 years ago
three students went out for lunch in a restaurant Sophie ordered the business special for $8.50 Lauren ordered a full meal with
katen-ka-za [31]
Ok so first, you add $8.50, $10.25, and $2.25 to get the total bill of $21. Since 3 people are splitting the bill equally, divide $21 by 3 to get $7. Hope this is helpful!
5 0
3 years ago
Triangle ABC has side lengths: AB = 3.5 cm, BC = 2.4 cm, and AC = 4.2 cm ΔABC ≅ ΔHJK What is the length of side HJ?
Licemer1 [7]
For this you'll want to draw out Triangle ABC and label it as the problem gives you.

Draw a similar triangle to the first one you drew and label it the exact same way as "ABC" and then match the measurement "AB" to "HJ".

Hope this helps.
4 1
3 years ago
find x. assume that segments that appear tangent are tangent. please help need answer and how to do it.
Pavlova-9 [17]
Triangle ABC is a right triangle, meaning we can use the Pythagorean Theorem to find x.
The formula for the Pythagorean Theorem is:
a =  \sqrt{ {b}^{2}  +  {c}^{2} }
where a is the hypotenuse, and b and c are the legs.
In this problem, we have the vertical leg as 16, the horizontal leg as x, and the hypotenuse as 20. Therefore, we can say that
a = 20 \\ b = 16 \\ c = x
Therefore, we can plug into the formula to find x:a =  \sqrt{ {b}^{2}  +  {x}^{2} }  \\  {a}^{2}  =  { \sqrt{ {b}^{2}  +  {x}^{2} } }^{2}  \\  {a}^{2}  =  {b}^{2}  +  {x}^{2}  \\  {a}^{2}  -  {b}^{2}  =  {x}^{2}
We first change the variable c to x and square both sides of the equation. Then we subtract b^2 from both sides.
{x}^{2}  =  {a}^{2}  -  {b}^{2}  \\  \sqrt{ {x}^{2} }  =  \sqrt{ {a}^{2}  -  {b}^{2} }  \\ x =  \sqrt{ {a}^{2} -  {b}^{2}  }
We square root each side to find the variable answer for x. Then we plug in the numbers:x =  \sqrt{ {(20)}^{2} -  {(16)}^{2}  }  \\ x =  \sqrt{400 - 256}  \\ x =  \sqrt{144}  \\ x = 12
We find that x = 12. The answer is A. 12.
3 0
3 years ago
You are going to roll two dice. Let the variable x = the sum of the numbers rolled. What is the probability that x = 9 ?
natita [175]
Assuming these are two six-sided dice, you'll have 36 total combinations to test out. To get the 36, I just multiplied the 6 sides on both dice (6x6=36). First you have to test out all the possible combinations. Making it easier for you, I'll just list the ones that work. The combinations that work are 3+6, 4+5, 5+4, and 6+3. This means there are 4 combinations that work out of 36. This gives us the fraction 4/36. Now, this needs to be simplified. Both numbers are divisible by four, so we'll divide by four. The new fraction is 1/9, which is your answer. This means that, statistically speaking, if you rolled those two dice nine times, the sum of the numbers would be 9 only once. You have an 11% chance of having two numbers on the dice that have a sum of 9.
8 0
3 years ago
Read 2 more answers
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