The answer is B for increase of one year the events increase by 0.5
You can do this by using the eqn
y=0.5x-1.3
y=0.5(15)-1.3
y = 7.5-1.3
y = 6.2
y=0.5(16)-1.3
y=8-1.3
y=6.7
6.7-6.2 = 0.5
Answer:
Proved
Step-by-step explanation:
The given data is:
not 
Required
Prove by induction that it is divisible by 5
Assume 
So, we have:
where p is a positive digit
Rewrite as:

To solve further, we have to prove that
is true for 
So, we have:


Add 0

Replace 0 with 


Factorize

Substitute 


Factorize

Factorize
![11^{k+1} - 6 = 5[11(p + 1)- 1]](https://tex.z-dn.net/?f=11%5E%7Bk%2B1%7D%20-%206%20%3D%205%5B11%28p%20%2B%201%29-%201%5D)
<em>The 5 outside the bracket implies that it is divisible by 5</em>
The GCF is 4x so we can write:-
4x(5x^2 + 11)
Thats your answer
Farmer has 7 choice for cow out of which he choose only 2
4 choice for pig and he choose only 3 pigs
10 choice for sheep and he choose all 10 sheep
Number of ways of choosing cows = 7C2
Number of ways of choosing pigs = 4C3
number of ways of choosing sheep = 10C 10
all these three groups of different animals can make different groups when taken together
That is : 7C2 * 4C3 * 10C10 = 21 * 4 * 1 = 84 ways
Answer : 84
Answer:
C
Step-by-step explanation:
(2x+1) - (x²-7) = 2x + 1 - x²- + 7 = -x²- + 2x + 8