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Anit [1.1K]
4 years ago
13

10 points! I will thanks, rate, and give best answer!!

Mathematics
1 answer:
vfiekz [6]4 years ago
4 0
Answer: The fourth term is -102

----------------------------------------------

Explanation:

The term after the nth term is generated by this rule  a_{n+1} = -4(a_n) + 2 which means that we first
Step 1) multiply the nth term ( a_n ) by -4
Step 2) Add the result of step 1 to the value 2 to get the next term in the sequence

Let's follow those steps above to generate the first four terms

The first term is a_1 = 2. In short, the first term is 2

The second term is...
a_{n+1} = -4(a_n) + 2
a_{1+1} = -4(a_1) + 2
a_{2} = -4(2) + 2
a_{2} = -8 + 2
a_{2} = -6
So the second term is -6

The third term is...
a_{n+1} = -4(a_n) + 2
a_{2+1} = -4(a_2) + 2
a_{3} = -4(-6) + 2
a_{3} = 24 + 2
a_{3} = 26
The third term is 26

Finally, the fourth term is...
a_{n+1} = -4(a_n) + 2
a_{3+1} = -4(a_3) + 2
a_{4} = -4(26) + 2
a_{4} = -104 + 2
a_{4} = -102
The fourth term is -102.
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Answer correctly for brainliest and also a thanks ! Don't answer if you don't know it please !
Drupady [299]
The answer is B for increase of one year the events increase by 0.5

You can do this by using the eqn

y=0.5x-1.3
y=0.5(15)-1.3
y = 7.5-1.3
y = 6.2

y=0.5(16)-1.3
y=8-1.3
y=6.7

6.7-6.2 = 0.5
5 0
3 years ago
Given the statement 11^(n -6) is divisible by 5 for every positive integer n. What must be shown in the induction step?
Lilit [14]

Answer:

Proved

Step-by-step explanation:

The given data is:

11^n - 6 not 11^{n - 6

Required

Prove by induction that it is divisible by 5

Assume n = k

So, we have:

11^k - 6 = 5p where p is a positive digit

Rewrite as:

11^k = 5p + 6

To solve further, we have to prove that 11^k - 6 is true for n=k+1

So, we have:

11^{k+1} - 6

11^{k+1} - 6 = 11^k * 11 - 6

Add 0

11^{k+1} - 6 = 11^k * 11 - 6 + 0

Replace 0 with -5 +5

11^{k+1} - 6 = 11^k * 11 - 6 - 5 + 5

11^{k+1} - 6 = 11^k * 11 - 11- 5

Factorize

11^{k+1} - 6 = 11 (11^k - 1)- 5

Substitute 11^k = 5p + 6

11^{k+1} - 6 = 11 (5p + 6- 1)- 5

11^{k+1} - 6 = 11 (5p + 5)- 5

Factorize

11^{k+1} - 6 = 11 *5(p + 1)- 5

Factorize

11^{k+1} - 6 = 5[11(p + 1)- 1]

<em>The 5 outside the bracket implies that it is divisible by 5</em>

3 0
3 years ago
Factor this polynomial 20x^3+44x
Aleksandr [31]
The GCF is 4x   so we can write:-

4x(5x^2 + 11)

Thats your answer
5 0
3 years ago
Compute the permutations and combinations.A farmer buys 2 cows, 3 pigs, and 10 sheep from a seller who has 7 cows, 4 pigs, and 1
aliya0001 [1]

Farmer has 7 choice for cow out of which he choose only 2

4 choice for pig and he choose only 3 pigs

10 choice for sheep and he choose all 10 sheep

Number of ways of choosing cows = 7C2

Number of ways of choosing pigs = 4C3

number of ways of choosing sheep = 10C 10

all these three groups of different animals can make different groups when taken together

That is : 7C2 * 4C3 * 10C10 = 21 * 4 * 1 = 84 ways

Answer : 84

6 0
3 years ago
Read 2 more answers
For f(x)= 2x+1 and g(x)=x²-7, find (f-g)(x)<br> A.x²-2x-8<br> B.-x²+2x-6<br> C.-x²+2x+8<br> D.2x²-15
meriva

Answer:

C

Step-by-step explanation:

(2x+1) - (x²-7) = 2x + 1 - x²- + 7 = -x²- + 2x + 8

4 0
3 years ago
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