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Hatshy [7]
3 years ago
14

The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

er normally flows at a speed of 2 miles per hour. What must its speed be in order to transport particles that are 15 times as massive as usual? Round your answer to the nearest hundredth.
The speed of the river must be about ____ miles per hour.
Please explain how to do it I have the answer but don't know how to get to it.
Mathematics
1 answer:
kari74 [83]3 years ago
6 0
The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

The mass of the particles moving in river is proportional to the sixth power of 2, or 2^6 = 64 miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship x * 2^6 = k, for some constant k. 

For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

So, the key here is proportional. We can set up two proportions and cross multiply.

\dfrac{x}{2^6} =  \dfrac{15x}{y^6}  \\ (x)(y^6)=(2^6)(15x)

Cancelling our x's (because we don't need to solve for them), we have

y^6 = 15(2^6) = 15(64)=960

To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

\sqrt[6]{y^6} =  \sqrt[6]{960}

Using a calculator, we see that \sqrt[6]{960} = 3.14 \ miles \ per \ hour.
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Romashka-Z-Leto [24]

Answer:

Between 9:00 am and 10:45 am, there have been 1 hour and 45 minutes or 1.75 hours have passed. Let x be the speed of the slower cyclist and x+ 5 be the rate of the second cyclist. The given situation is best represented through the equation below,

                                x(1.75) + (x + 5)(1.75) = 47.25 km

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8 0
3 years ago
Read 2 more answers
Please help. I’ll mark you as brainliest if correct!
balu736 [363]

Answer: x= -1, z=2, y= -4

Step-by-step explanation:

System of equations:

-5x - 4y - 3z= 15  +

<u>-10x + 4y + 6z= 6</u>

-15x         + 3z = 21  ------>  3 (-5x + z) = 7.3

-5x + z = 7

now,

-10x + 4y + 6z= 6

2(-5x + z) + 4y + 4z = 6

14 + 4y + 4z = 6

7 + 2y + 2z = 3

2y + 2z= -4

y+z=-2

Now we were using the equation: 20x + 4y + 4z = -28

20x + 4(y+z) = 20x -8= - 28

20 x = -20

x= -1

With this we can find y and z

X=-1

-5x + z = 7

z= 2

y+z=-2

y=-4

Finally we have: x= -1, z=2, y= -4

I hope this can help you.

Thank you

3 0
3 years ago
Which is equivalent to 80^1/4x
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80^\frac{1}{4}x=x\sqrt[4]{80}=x\sqrt[4]{16\cdot5}=x\sqrt[4]{16}\cdot\sqrt[4]5=2x\sqrt[4]5
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Answer:

Step-by-step explanation:

Solve 8-3y<41.

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3 years ago
Find the difference between <br> 10 and −25 (Hint: Subtract the numbers in the order given.)
gladu [14]
The difference is -15
7 0
2 years ago
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