Answer:
D. 2x^2-7x.
Step-by-step explanation:
Lets write it out to make it easy to work with.
-x(-2x+7)
Multiply the -x out
2x^2-7x.
The answer is D
3pi/7 < pi/2 because 3/7 < 1/2, and pi/2 is a right angle. Conclusion: the angle opposite side a is an acute angle. In this situation the triangle could be a right triangle, in which case C would be true, but it does not have to be a right triangle, so don´t choose C. Similarly, it could be an acute triangle, in which case B would be true, but it does not have to be, so don´t choose B. Also, A says the angle opposite side a is obtuse, which is false. So don´t choose A. That leaves D, which says the angle opposite side a is acute, which we know is true. So the answer is <span>D. b^2 + c^2 > a^2</span>
Answer:
c=(10)($1.75)/12
c=$17.50/12
c=$1.458 which rounds to $1.46 per token
Answer:
So, the first three nonzero terms in the Maclaurin series are:
Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:
So, for the given function y = 6 sec(3x), we get:
So, the first three nonzero terms in the Maclaurin series are:
Answer:
Josh is wrong.
Step-by-step explanation:
5^-x / 5^x = 5^(-x-x) = 5^-2x
= 1 / 5^2x
(you subtract the exponents when dividing )
So Josh is wrong ( he would be correct if we were multiplying)
