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Rufina [12.5K]
3 years ago
9

in a parking lot 60% of the cars are four-door cars.If there are 75 four-door cars in the parking lot how many cars are in the p

arking lot all together?​
Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

there are 125 cars in the parking lot

Step-by-step explanation:

You might be interested in
Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
3 years ago
3 times 5 with a two on the top
jenyasd209 [6]
Ok so it could be
1. \frac{2}{3 times 5}
2. 3 timies \frac{2}{5}


ok if 1. then
\frac{2}{3 times 5}=\frac{2}{15}

if 2.  3 timies \frac{2}{5}= \frac{6}{5}



3 0
3 years ago
Please help I really really really need assistance through any means!
Georgia [21]
So make a square and then you an answer from (0,1) to (4,3) the slope is 1/2 in simplest form, but for a more accurate answer a calculator. 
8 0
4 years ago
Read 2 more answers
Given the parent function
lozanna [386]

Answer:

Option c is right.

Step-by-step explanation:

Given is a parabola y =x^2

From that transformation is done to get parabola as

y =(0.2x)^2

We find that instead of x here we use 0.2x

i.e. New x = 5 times old x

Hence there is a horizontal expansion of scale factor 5.

We can check with any point also

When y =4, x=2 in the parent graph

But when y =4 , we have x = 10 in the new graph

i.e. there is a horizontal expansion of scale factor 5.

7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
Nutka1998 [239]

Let i = sqrt(-1) which is the conventional notation to set up an imaginary number

The idea is to break up the radicand, aka stuff under the square root, to simplify

sqrt(-8) = sqrt(-1*4*2)

sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)

sqrt(-8) = i*2*sqrt(2)

sqrt(-8) = 2i*sqrt(2)

<h3>Answer is choice A</h3>
5 0
3 years ago
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