Answer: 3x-7y
Step-by-step explanation:
9x-6x=3x you can't do anything with the y
'Nates classroom has three tables'
Well, that's true.
Rule 1: The product<span> of a positive </span>integer<span> and a negative </span>integer<span> is a negative </span>integer<span>. Rule 2: The </span>product of two<span> negative </span>integers<span> or </span>two<span> positive </span>integers<span> is a positive </span><span>integer</span>
Answer: -11
Step-by-step explanation:
For this problem, it is important to look at the domains next to the function. In this problem there is a function for when x < 1 and when x ≥ 1. 3 is greater than 1, so we will use the second equation.
From there, plug in 3 for x and solve.
-2x - 5
-2(3) - 5
-6 - 5
-11
The numbers are: 36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables;
"x" and "y" .
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x + y = 47 .
y − x = 25.
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Since: " y − x = 25 " ;
Solve for "y" in terms of "x" ;
y − x = 25 ;
Add "x" to each side of the equation:
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y − x + x = 25 + x ;
to get:
y = 25 + x .
Now, since:
x + y = 47 ;
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47 ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x = 22 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; and to solve for "x" ;
2x / 2 = 22 / 2 ;
x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
to isolate "y" on one side of the equation; and to solve for "y" ;
11 + y − 11 = 47 − 11 ;
y = 36 .
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So: x = 11 , y = 36 ;
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Let us check our work:
y − x = 25 ;
36 − 11 =? 25 ? Yes!
x + y = 47 ;
36 + 11 =? 47 ? Yes!
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The numbers are: 36 and 11 .
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