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4 years ago

Which is the solution set of the compound inequality 3.5x-10>-3and 8x-9<39

Mathematics

1 answer:

dimulka [17.4K]4 years ago

8 0

So to solve for an inequality, you must isolate the variable, in this case x, to one side.

Starting with 3.5x - 10 > -3, firstly add both sides by 10:

3.5x > 7

Next, divide both sides by 3.5 and your first half is:

x > 2

Next with 8x - 9 < 39, firstly add both sides by 9:

8x < 48

Next, divide both sides by 8 and your second half is:

x < 6

<u>Putting it together, your final answer is x > 2 and x < 6 or 2 < x < 6.</u>

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The equation below shows the total volume (V), in cubic units, of 4 identical boxes with each side equal to s units: V = 4s3 If

dexar [7]

Hello!
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4 0

4 years ago

Read 2 more answers

Help I’m lost and don’t understand

kobusy [5.1K]

Answer:

27 t-shirts

Step-by-step explanation:

First, set up an equation. Using T as the unknown number of t-shirts, we see:

50 + 3T = 131

3T = 81

T=27 t-shirts

Hope that helps!

7 0

3 years ago

Read 2 more answers

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

laiz [17]

Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of $(h\circ g)(-6)$ is 2401.

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3 years ago

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DochEvi [55]

Okurrrrr how u doin mate

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3 years ago

What is2.3684 roundes to the neareat thousandth

shusha [124]

<span>2.3684 rounded to the nearest thousandths is 2.368

</span>

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4 years ago