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3 years ago

How do I find the perimeter of the shapes

Mathematics

1 answer:

Katen [24]3 years ago

8 0

Answer:Here is the answer

Step-by-step explanation: You first break the shape into two different shapes.Then add them side by side. Determine the length for each side. Then add them together. Add both of the perimeters of the shapes.

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Please answer this question!! 30 points and brainliest!

12345 [234]

Answer:

2 out of 8 or 25 %

Step-by-step explanation:

8 0

3 years ago

Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

Let's verify each case to determine the solution

case A) $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

case B) $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

case C) $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

case A) $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

the answer is

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

6 0

3 years ago

Read 2 more answers

Simplify Negative two and one-third minus negative ten and one-sixth

aivan3 [116]

-2 1/3 - (- 10 1/6) =
- 7/3 + 61/6 =
-14/6 + 61/6 =
47/6....or 7 5/6

6 0

4 years ago

Whats is the mean in -10 + -10 + 6 + 5 + -1 + -1 ???? PLZ HELP

Black_prince [1.1K]

-11 is the correct answer

6 0

3 years ago

Read 2 more answers

Write x as a logarithm in the following: 10^x=7

pochemuha

Answer:

x = log 7

Step-by-step explanation:

10^x=7

Take the log base 10 on each side

log10 (10^x)=log10 (7)

We dont need to write the 10, it is implied

log(10^x)=log (7)

The exponent goes out front since log a^b = b log a

x log 10 = log 7

log 10 = 1 since the base is 10 log10(10) =1

x = log 7

6 0

3 years ago

Read 2 more answers