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gtnhenbr [62]
3 years ago
7

Using side lengths only ,could triangles be similar

Mathematics
1 answer:
olga55 [171]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Only if corresponding side lengths are all equally proportional to each other.  They each have to share the same multiple with their corresponding side

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Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0
3 years ago
Witch expression represents a number 5 times the difference of 6 and 2
nikklg [1K]

Answer:

i think it is 20

Step-by-step explanation:

6-2=4

4×5=20

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Step-by-step explanation:

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section covers somplifying algebraic expressions

Step-by-step explanation:

<h3>(4x^{3})(2x^{-4}) = \frac{4x^{3} }{2x^{4} } = 2/x⇒</h3>
7 0
2 years ago
Need ASAP plz help!! These are the numbers you use. <br>15 27 28 31 34 42 52
Dahasolnce [82]

im sorry but did you ever get the answer?


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