All categories

2 years ago

Can someone help me here please!?

Mathematics

2 answers:

Maksim231197 [3]2 years ago

7 0

The answer is A p = 1.6m

irina [24]2 years ago

5 0

The answer would be A, because if I did 1.6×5, I would get an answer of 8 and if i did 1.6×15, I would get 24 ,so Option A is the answer.

You might be interested in

What is the y-intercept of function f? A. 1 B. -1 C. -2 D. 5

shtirl [24]

Answer:

Step-by-step explanation:

The y intercept is when x =0

We need to use the second equation

-x+1 since -2 < 0 <3

0+1

The y intercept is 1

5 0

3 years ago

If f(x)=2x and g(x)= 1/x, what is the domain of (f*g) (x)

postnew [5]

Answer:

The domain of (f*g) (x) is the set of all real numbers; ( -∞, ∞)

Step-by-step explanation:

(f*g) (x) simply means we obtain the product of f(x) and g(x). We are given that;

f(x)=2x

g(x)= 1/x

(f*g) (x) = f(x) * g(x)

(f*g) (x) = 2x * 1/x = 2

This is a horizontal line defined everywhere on the real line. The domain of (f*g) (x) is thus ( -∞, ∞)

7 0

3 years ago

Read 2 more answers

The segment with endpoints (0,8) and (−6,0) is dilated to a segment with endpoints (0, 6) and (−4.5,0). What is the scale factor

sergiy2304 [10]

I think it would be 4/3 because when you multiply 8 by 4/3 you get 6 and when you multiply-6 by 4/3 you get -4.5 so

4/3

5 0

2 years ago

What value of n makes the equation true?

Naddik [55]

Answer:

n = 5.2.

Step-by-step explanation:

-20.8 = -4n

We divide both sides of the equation by -4:

-20.8 / -4 = -4n/-4

5.2 = n (answer).

4 0

2 years ago

Read 2 more answers

Write a linear equation that passes through the two points (-6, -7) and (3, -4).

Phantasy [73]

linear equation that passes through the two points (-6, -7) and (3, -4) is $y=\frac{1}{3}x-5$

Step-by-step explanation:

We need to write the equation that passes through the two points (-6, -7) and (3, -4).

The equation can be written is point slope form.

The standard form of point slope equation is:

$y=mx+b$

where m is the slope and b is the y-intercept

Finding slope m:

Slope can be found by using formula:

$slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=-4,y_{1}=-7,x{2}=3,x_{1}=-6\\slope =\frac{-4-(-7)}{3-(-6)}\\slope=\frac{-4+7}{3+6}\\slope=\frac{3}{9}\\slope=\frac{1}{3}$

So, slope is $\frac{1}{3}$

Now finding y-intercept b

Putting slope $\frac{1}{3}$ and point(-6,-7)

$y=mx+b\\x=-6,y=-7,m=\frac{1}{3} \\-7=\frac{1}{3}(-6)+b\\-7=-2+b\\b=-7+2\\b=-5$

So, value of b is -5

Putting values to find the equation:

$y=mx+b\\m=\frac{1}{3} and b=-5\\y=\frac{1}{3}x-5$

So, linear equation that passes through the two points (-6, -7) and (3, -4) is $y=\frac{1}{3}x-5$

Keywords: Linear Equation,

Learn more about Linear Equation at:

#learnwithBrainly

5 0

3 years ago