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Sever21 [200]
3 years ago
9

Can someone help me here please!?

Mathematics
2 answers:
Maksim231197 [3]3 years ago
7 0
The answer is A p = 1.6m
irina [24]3 years ago
5 0
The answer would be A, because if I did 1.6×5, I would get an answer of 8 and if i did 1.6×15, I would get 24 ,so Option A is the answer.
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A fence is 692 m long. It is cut into three parts. Two parts are the same length, and the third part is 26 m longer than either
xenn [34]
One is 222
Two is 222
Three is 248
7 0
3 years ago
5/2+18/5+11/4 what is the answer for this question​
Likurg_2 [28]

Answer:

Step-by-step explanation:

basicallyi you want to find a common denominator before you add them up. the common denominator in this case would be 20, since it's the first common multiple all of them share

50/20 plus 72/20 plus 55/20

177/20 would be your answer

3 0
3 years ago
Read 2 more answers
Needing help to find the inequality
tiny-mole [99]

http://goblues.org/faculty/grantm/files/2015/12/Practice-Test-3.7-Solutions.pdf

I think it's question number three. Sorry if the link dosen't work.

4 0
3 years ago
Let H be an upper Hessenberg matrix. Show that the flop count for computing the QR decomposition of H is O(n2), assuming that th
aleksley [76]

Answer:

Answer is explained in the attached document

Step-by-step explanation:

Hessenberg matrix- it a special type of square matrix,there there are two subtypes of hessenberg matrix that is upper Hessenberg matrix and lower Hessenberg matrix.

upper Hessenberg matrix:- in this type of matrix  zero entries below the first subdiagonal or in another words square matrix of n\times n is said to be in upper Hessenberg form  if ai,j=0

for all i,j with i>j+1.and upper Hessenberg matrix is called unreduced if all subdiagonal entries are nonzero

lower Hessenberg matrix:-  in this type of matrix  zero entries upper the first subdiagonal,square matrix of n\times n is said to be in lower Hessenberg form  if ai,j=0  for all i,j with j>i+1.and lower Hessenberg matrix is called unreduced if all subdiagonal entries are nonzero.

8 0
3 years ago
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud
SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given  population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }

The 85% confidence level z_{\alpha } = 1.44

\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}

\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

7 0
3 years ago
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