Answer: XY=15
Step-by-step explanation:
I just took the test
Answer:
3.52x
Step-by-step explanation:
Let
Quantity of tickets=4
Price of tickets=x
Discount=12%
This means, you will pay 100% -12%
=88%
Total amount payable=discount (quantity * price)
= 88% ( 4 * x )
= 0.88 (4x)
= 3.52x
Answer:
Abby's mother spent $9.75 for the classroom not including tax.
Step-by-step explanation:
Know:
5 bags for 1 dollar
10 candy bars for 50 cents
3 whistles for 75 cents
5×6=30
10×3=30
3×10=30
- 5 times 6 is thirty. So find the product of 6 and 1 which is 6. 6 is the overall cost of bags.
- 10 times 3 is 30. So find the product of 3 and .50 which is 1.50. 1.50 dollars is the overall cost of candy bars.
- 3 times 10 is 30. You then find the product of 3 and .75. The product of this is 2.25 which is the total cost of whistles.
- Next you add all the values together which are 6.00 + 1.50 + 2.25 this equals $9.75
Answer:
y - 11 = 3 (x - 2)
Step-by-step explanation:
This is in point slope form, that is by far the best form to be in. Point slope form is best when there is a point and it gives it to you in slope intercept form. you take the slope from the original equation and stick it into y - (y point) = slope (x - (x point)) you know it is the right equation because it gives you the slope, which is the same, and the point, which is given.
The way to get it into slope intersept form you just solve for y
Answer:
<h2>x = 9 and y = -3 → (9, -3)</h2>
Step-by-step explanation:
![\left\{\begin{array}{ccc}\dfrac{1}{3}x+y=\dfrac{0}{3}&\text{multiply both sides by 3}\\\\\dfrac{1}{6}x+\dfrac{1}{5}y=\dfrac{9}{10}&\text{multiply both sides by 30}\end{array}\right\\[tex]\left\{\begin{array}{ccc}x+3y=0&\text{multiply both sides by (-2)}\\5x+6y=27\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-2x-6y=0\\5x+6y=27\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad3x=27\qquad\text{divide both sides by 3}\\.\qquad\boxed{x=9}\\\\\text{Put the value of x to the first equation:}\\\\9+3y=0\qquad\text{subtract 9 from both sides}\\3y=-9\qquad\text{divide both sides by 3}\\\boxed{y=-3}](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D%5Cdfrac%7B1%7D%7B3%7Dx%2By%3D%5Cdfrac%7B0%7D%7B3%7D%26%5Ctext%7Bmultiply%20both%20sides%20by%203%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B6%7Dx%2B%5Cdfrac%7B1%7D%7B5%7Dy%3D%5Cdfrac%7B9%7D%7B10%7D%26%5Ctext%7Bmultiply%20both%20sides%20by%2030%7D%5Cend%7Barray%7D%5Cright%5C%5C%5Btex%5D%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx%2B3y%3D0%26%5Ctext%7Bmultiply%20both%20sides%20by%20%28-2%29%7D%5C%5C5x%2B6y%3D27%5Cend%7Barray%7D%5Cright%5C%5C%5Cunderline%7B%2B%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D-2x-6y%3D0%5C%5C5x%2B6y%3D27%5Cend%7Barray%7D%5Cright%7D%5Cqquad%5Ctext%7Badd%20both%20sides%20of%20the%20equations%7D%5C%5C.%5Cqquad3x%3D27%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%203%7D%5C%5C.%5Cqquad%5Cboxed%7Bx%3D9%7D%5C%5C%5C%5C%5Ctext%7BPut%20the%20value%20of%20x%20to%20the%20first%20equation%3A%7D%5C%5C%5C%5C9%2B3y%3D0%5Cqquad%5Ctext%7Bsubtract%209%20from%20both%20sides%7D%5C%5C3y%3D-9%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%203%7D%5C%5C%5Cboxed%7By%3D-3%7D)
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