Answer:
x = 16
m<Y = 34°
Step-by-step explanation:
∆XYZ is an isosceles ∆. An isosceles ∆ has two equal sides, as well as the bases of the isosceles triangle are congruent. In this case, therefore:
<X = <Z
(6x - 23)° = (4x + 9)
Solve for x
6x - 23 = 4x + 9
Collect like terms
6x - 4x = 23 + 9
2x = 32
Divide both sides by 2
x = 16
m<Y = 180° - (m<X + m<Z) (sum of ∆)
m<Y = 180 - ((6x - 23) + (4x + 9))
Plug in the value of x
m<Y = 180 - ((6(16) - 23) + (4(16) + 9))
m<Y = 180 - (73 + 73)
m<Y = 34°
Answer: the value of her investment after 4 years is £8934.3
Step-by-step explanation:
The formula for determining compound interest is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount invested.
t represents the duration of the investment in years.
From the information given,
P = 8000
r = 2.8% = 2.8/100 = 0.028
n = 1 because it was compounded once in a year.
t = 4 years
Therefore,
A = 8000(1+0.028/1)^1 × 4
A = 8000(1+0.028)^4
A = 8000(1.028)^4
A = £8934.3 to the the nearest penny
Answer: The value of x =2 units.
Explanation:
Since we have given that
AD= CD
BE= EA
So, we get that D and E are the mid-points of AC and AB respectively.
So, by Mid- point theorem , which states that the line joining the two midpoints is parallel to third side and it is half in length of third side i.e.
![DE=\frac{1}{2}BC](https://tex.z-dn.net/?f=DE%3D%5Cfrac%7B1%7D%7B2%7DBC)
So, we put the value of DE and BC ,
![5x-3=\frac{1}{2}\times (x+12)\\\\2(5x-3)=x+12\\\\10x-6=x+12\\\\10x-x=12+6\\\\9x=18\\\\x=\frac{18}{9}=2](https://tex.z-dn.net/?f=5x-3%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%28x%2B12%29%5C%5C%5C%5C2%285x-3%29%3Dx%2B12%5C%5C%5C%5C10x-6%3Dx%2B12%5C%5C%5C%5C10x-x%3D12%2B6%5C%5C%5C%5C9x%3D18%5C%5C%5C%5Cx%3D%5Cfrac%7B18%7D%7B9%7D%3D2)
Hence, the value of x =2 units.
The measure of arc PO is 173 degrees
Step-by-step explanation:
![1 \div 100th](https://tex.z-dn.net/?f=1%20%5Cdiv%20100th)