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Ksenya-84 [330]
3 years ago
11

SOMEONE PLZ HELP ME ON THIS PROBLEM!!!!! I WILL GIVE BRAINLIEST TO THE BEST ANSWER!!!!!

Mathematics
2 answers:
STALIN [3.7K]3 years ago
6 0

Answer:

<h2>             D. </h2><h3>They have different y-intercepts but the same end behavior</h3>

Step-by-step explanation:

Let's name the function from graph: f

for f:

y-intercept = f(0) = 4

for x → ∞,  f(x)→2

for g:

y-intercept = f(0) = 4(¹/₄)⁰+2 = 4•1+2 = 4+2 = 6 ≠4

f(1) =  4(¹/₄)¹+2 = 4•¹/₄+2 = 1+2 = 3

f(2) =  4(¹/₄)2+2 = 4•¹/₁₆+2 = ¹/₄+2 = 2¹/₄

f(3) =  4(¹/₄)³+2 = 4•¹/₆₄+2 = ¹/₁₆+2 = 2¹/₁₆

f((5) =  4(¹/₄)⁵+2 = 4•¹/₁₈₂₄+2 = ¹/₅₁₂+2 = 2¹/₅₁₂

....

so for x x → ∞,  f(x)→2

NeX [460]3 years ago
4 0

Answer:

D

Step-by-step explanation:

End behaviour refers to the asymptotes, which both exponential functions have the same one at y = 2. However, they have different y - intercepts. The first one has a y - intercept of 4 and the second one has a y - intercept of 6. Thus, the answer is D.

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