Answer:
D
Step-by-step explanation:
out of the choices
A) 2x-y=-2
3x+2y=-10
B) x+4y=3
2x+5y=3
C) 2x+3y=5
x-4y=-14
D) 3x+4y=15
x+y=5
only the system in D has a solution of x=5 and y=0
solve by substitution x+y=5 so x=5-y
plug into the other equation so 3(5-y)+4y=15
distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms
so y=0 then put that value back into the other equation
so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)
Hope this helps! :)
This is an equation in STANDARD form for a circle:
(x-h)^2 + (y-k)^2 = r^2
The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa.
The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1.
(x)^2 + (y-6)^2 = 1
Answer:
$0.25
Step-by-step explanation:
2.99/12 aprrox. equals 25 cents
Answer:
4th box and 1st box
Step-by-step explanation:
I learned this 7th nd passed it so u should be chillin
