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den301095 [7]
3 years ago
7

What is the least common multiple of 3 and 9

Mathematics
2 answers:
Tju [1.3M]3 years ago
5 0

LCM(3, 9) = 9

because 9 = 3 × 3

tangare [24]3 years ago
5 0

Answer:

Step-by-step explanation:

thatnk you sir

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PLZZZZZZZ NEED HELP!!!!!!!!!
Angelina_Jolie [31]
The first option is the correct choice of answers.
4 0
3 years ago
Math 7 A Unit 4 lesson 2 Please help quick<br>5/10-3/10<br>1/2+3/4<br>1/6+3/8<br>7/8-5/12
velikii [3]

Answer:

2/10, 1 1/4, 13/24, 11/24

Step-by-step explanation:

1. subtract the fractions

2. add the fractions

3. add the fractions

4. add the fractions

3 0
2 years ago
Which numerical descriptive measure shows whether two numerical variables have a linear relationship
Brrunno [24]

Answer:

Correlation Coefficient

Step-by-step explanation:

Correlation Coefficient: The correlation coefficient is a numerical measure that measures the strength and direction of a linear relationship between two quantitative variables.

3 0
2 years ago
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
Find the area of the figure.<br> square with sides of 5.7 ft<br> The area of the square is<br> ft2
ozzi

Answer:

32.5 ft^2

Step-by-step explanation:

All sides of a square have the same length.  Area would therefore be:

 (5.7 ft)(5.7 ft) = 32.5 ft^2

7 0
2 years ago
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