1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
diamong [38]
3 years ago
12

State the domain of the rational function. (2 points)

Mathematics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

All real numbers except 4.

Step-by-step explanation:

The given function is

f(x)=\frac{6}{4-x}


This is a rational function.


The domain of a rational function is all real numbers except values that will make the denominator zero.


The denominator of the given function is 4-x.


So the domain is all real numbers except

4-x=0

We solve for x to obtain,

4=x or x=4.


Therefore the domain is all real numbers except x=4.

You might be interested in
Presley is deciding where to purchase cat food for his pet. He is considering PetCo and Chewy. PetCo currently has a sale on Fan
navik [9.2K]

PetCo:

t = 0.52c + 41.99

Chewy:

t = 0.64c + 36.98

3 0
3 years ago
15x + 20xy = 5x(4y) <br> Are these two Equivalent
mixas84 [53]

Answer:

no

Step-by-step explanation:

on the first equation there are two Xs

6 0
3 years ago
The relation R is shown below as a list of ordered
Dmitrij [34]

Answer:

(1, 4) and (1,3), because they have the same x-value

Step-by-step explanation:

For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.

In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.

Therefore, the relation is not a function anymore if both ordered pairs are included.

<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>

7 0
3 years ago
A car dealership has found that the length of time before a major repair is required on the new cars it sells is normally distri
weqwewe [10]

Answer:

Step-by-step explanation:

Hello!

The variable of interest in this case is:

X: length of time before a major repair is required on a new car. (months)

This variable has a normal distribution with mean μ= 36 months and a standard deviation σ= 9 months.

If he wants to set a guarantee period in which only 5% of the sold cars fell, the objective is to find the value of X that has below 5% of the cars that need major repairs before the end of the guarantee period.

Check the attachment, the curve represents the distribution of the population of the time it takes before a new car needs major repairs, I've marked approximately where this value of X should be.

Symbolically:

P(X≤a)=0.05

To reach the proper value of "a" you have to work using the standard normal distribution because is a tabulated distribution and you can extrapolate it to any normal distribution.

Z= \frac{X-Mu}{Sigma}~N(0;1)

So the first step is to look in the table of the Z distribution for the value that accumulates 0.05 of probability since it is such a low probability, you have to look for the value in the left side of the table (negative values of Z). You look for 0.05 in the body of the table and then the margins for the corresponding value (see second attachment)

Z_{0.05}= -1.64

Then the value that accumulates 0.05 of probability is -1.64, now you have to reverse the standardization to reach the asked value of X

Z= (a- μ)/σ

(Z*σ)= a - μ

a=(Z*σ)+ μ

a=(-1.64*9)+36

a= 21.24 months.

The guarantee period should be 21.24 months so that only 5% of the sold cars will need major repairs before it wears of.

I hope it helps!

5 0
3 years ago
1
Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

c = k/d

5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

10 = 9k

k = 10/9

c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

c = 10/9d

find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

8 0
3 years ago
Other questions:
  • Find all intervals on which the graph of f(x)=(x-1)/(x+3) is concave upward
    13·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%7B14x%7D%5E%7B4%7D%20%20%7By%7D%5E%7B7%7D%20%20%5Cdiv%20%20%7B6x%7D%5E%7B5%7D%20%20%7By%7D
    15·1 answer
  • Find the missing side to the triangle in the attached image.
    6·2 answers
  • Simplify 5(81/3 + 241/3)1/4
    9·2 answers
  • The cost of 7 scarves is $50.75. What is the unit price? The unit price is $ per scarf.
    5·1 answer
  • Solve the system by substitution.<br> y = -7x + 6<br> 5x + y = 2
    5·1 answer
  • Help plz ill give extra points
    7·2 answers
  • Which functions are not one-to-one functions?
    12·1 answer
  • can you find the lengths and area and type the correct code? Please remember to type in all caps with no space​
    5·2 answers
  • <img src="https://tex.z-dn.net/?f=48x2y%E2%88%9212xy2%E2%88%9260x2y2" id="TexFormula1" title="48x2y&minus;12xy2&minus;60x2y2" al
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!