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|First of all, the triangles are equal by ASA the way the diagram has been marked.
B and E are both right angles.
Side BC = Side DE
<BCA =< EDA
So triangle BCA = triangle EDA
Now to the letters.
x = y - 1 Add 1 to both sides.
x + 1 = y (1)
3x - 2 = 2y + 1 Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y (2)
Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.
1.5x - 1.5 = x + 1 Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1 Add 1.5 to both sides.
0.5x = 1 + 1.5
0.5x = 2.5 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5
x = 5
Now we need a y value.
x = y - 1
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y
So the 2 sides and the 2 angles are equal when
x = 5
y = 6
C Answer <<<<<<
Answer:
6
Step-by-step explanation:
2x-m
When you substitue in the values for x and m:
2(4)-2
Now you can solve the equation:
2(4)-2
8-2
6
So this leads to the answer
2x-m=6 or 2(4)-2=6
Answer:
The fraction of wood used for horizontal support is
.
Step-by-step explanation:
Assume that the total piece of wood is of length 1.
It is provided that Talia used
of the piece of wood for the base of he project.
She use
of the piece of wood for the for the vertical support.
The remaining wood she used for horizontal support.
The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.
Compute the amount of wood used for horizontal support as follows:

Thus, the fraction of wood used for horizontal support is
.