All categories

2 years ago

What is the length of the segment joining the points at (-6, 8) and (6, 3)?

Mathematics

1 answer:

melisa1 [442]2 years ago

7 0

Answer:

13 units

Step-by-step explanation:

So the length of those 2 points is 6+6 = 12.

The height would be 8-3 =5

Using pythagoras, you can find out the length of the line joining the 2 points so:

$5^2 + 12^2 = 169$

$\sqrt{169} = 13$ units

You might be interested in

Hell help me out thank youuuuuu byeee

Crank

Answer:

if im right its number 4!! if its not right sorry i did the math and thats what i got!!

4 0

3 years ago

If sally earns income of $80,000.00per yr. the 2.5% is taken out what will be sally's school taxes per yr.?

STALIN [3.7K]

Change the percentage into a decimal and multiply for the answer.

$80,000 * .025 = $2,000

3 0

3 years ago

Read 2 more answers

Vincent wrote an example of a proportion on the board.

Agata [3.3K]

Answer:

Vincent’s proportion is incorrect. His corresponding parts are not in the same position. The heights and bases are in different positions.

Step-by-step explanation:

I got it right on my assignment

7 0

3 years ago

Read 2 more answers

The prism shown has a volume of 35 cm.

Fiesta28 [93]

Answer:

the height is 2.5 cm

Step-by-step explanation:

The computation of the height of the triangular section is shown below:

As we know that

Volume = One-half × base × height

35 = One-half × 4 × height × 7

So, the height is 2.5 cm

7 0

2 years ago

Read 2 more answers

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

3 years ago