What is the length of the segment joining the points at (-6, 8) and (6, 3)?
1 answer:
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<h3>Therefore they are perpendicular.</h3>
Step-by-step explanation:
A equation of line is
y =mx +c
Here the slope of the line is m.
Given equations are
x - 2y = 18
⇔-2y = -x +18
............(1)
and 2x + y = 6
⇔y = -2x +6 ............(2)
Therefore the slope of equation (1) is=
Therefore the slope of equation (2) is= -2
If two lines are perpendicular, when we multiply their slope we get -1.
therefore,
=
. (-2) = -1
Therefore they are perpendicular.
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
