How could I Answer With Work

Elenna [48]

The answer is (x+5)(x-8)
Hope this helps

8 0

3 years ago

The owner of a factory wants to determine a confidence interval for the average wages at his factory. The population average wag

iVinArrow [24]

4,034.06 ,5,965.94 are confidence interval for the population average wages at the factory.

What is confidence interval estimation?

Your estimate's mean plus and minus the range of that estimate's fluctuation is called a confidence interval.

If you repeat your test, you can expect your estimate to fall between these numbers with a reasonable degree of certainty. Another term for probability in statistics is confidence.

The formula for confidence interval estimation is:

μ = M ± Z(sM)

where:

M = sample mean

Z = Z statistic determined by confidence level

sM = standard error = √(s2/n)

M = 50000

Z = 2.58

sM = √(30002/64) = 375

μ = M ± Z(sM)

μ = 50000 ± 2.58*375

μ = 50000 ± 965.94

μ = 4,034.06 ,5,965.94

Learn more about confidence interval

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6 0

1 year ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

tensa zangetsu [6.8K]

Answer:

$y=3t^9+C$

Step-by-step explanation:

Given: $\dfrac{dy}{dt}=27t^8$

We want to obtain the general solution of the given differential equation.

$dy=27t^8$ dt\\$Take the integral of both sides\\\int dy =\int 27t^8$ dt$\\y=\dfrac{27t^{8+1}}{8+1} +C$, (where C is the constant of integration)$\\y=\dfrac{27t^{9}}{9} +C\\\\y=3t^9+C$

The general solution of the differential equation is: $y=3t^9+C$

CHECK:

$\dfrac{d}{dt} y=\dfrac{d}{dt}(3t^9+C)=\dfrac{d}{dt}(3t^9)+\dfrac{d}{dt}(C)\\\\\text{Since derivative of a constant is zero}\\\\\dfrac{dy}{dt}=27t^{9-1}\\\dfrac{dy}{dt}=27t^8$

4 0

3 years ago

I need help solving this problem

zloy xaker [14]

9514 1404 393

Explanation:

When something is subtracted from both sides of the equation, the justification is the <em>subtraction property of equality</em>. When something multiplies both sides of the equation, the justification is the <em>multiplication property of equality</em>. (This should not be a mystery.)

Here, the equation is solved by subtracting 17/3, then subtracting 1/2x, then multiplying by the inverse of the coefficient of x. After each of these steps is a simplification.

$\begin{array}{cc}\dfrac{17}{3}-\dfrac{3}{4}x=\dfrac{1}{2}x+5&\text{given}\\\\\dfrac{17}{3}-\dfrac{3}{4}x-\dfrac{17}{3}=\dfrac{1}{2}x+5-\dfrac{17}{3}&\text{subtraction property ...}\\\\-\dfrac{3}{4}x=\dfrac{1}{2}x-\dfrac{2}{3}&\text{simplify}\\\\-\dfrac{3}{4}x-\dfrac{1}{2}x=\dfrac{1}{2}x-\dfrac{2}{3}-\dfrac{1}{2}x&\text{subtraction property ...} \end{array}$

$\begin{array}{cc}-\dfrac{5}{4}x=-\dfrac{2}{3}&\text{simplify}\\\\-\dfrac{5}{4}x\times-\dfrac{4}{5}=-\dfrac{2}{3}\times-\dfrac{4}{5}&\text{multiplication property ...}\\\\x=\dfrac{8}{15}&\text{simplify} \end{array}$

4 0

3 years ago

Need help with this math problem

Andre45 [30]

Hey There!

First you would need to factor out the two.

-4x^3/2 = -2x^3

2x^2/2= x^2

12x/2= 6x

6/2= 3

Now we have.

-2x^3+x^2+6x+3 / x+1

We would then factor with polynomial division, and then we should have.

-2(2x^2 - 3x - 3)(x+1) / x+1

We would then cancel out the x+1

Therefore, the answer would be $\boxed{-2(2x^2-3x-3)}$

Hope this helped!

8 0

3 years ago